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3 years ago

Write the first and second ionization equations for H2SeO3 please.

1 answer:

3 0

As a diprotic acid, the H₂SeO₃ can ionize by step. First step is H₂SeO₃ =(reversible reaction) H⁺ + HSeO₃⁻. And second step is HSeO₃⁻ =(reversible reaction) H⁺ +SeO₃ ²⁻.

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CADMIUM SOLUBILITY AND pH Cadmium is a toxic metal. It can be removed from water by chemical precipitation of solid cadmium hydr

Serga [27]

Explanation:

It is known that,

Molar mass of Cd = 112.41 g/mol

Standard concentration of Cd = 0.005 mg/L = $0.005 \times 10^{-3}$ g/L

Hence, we will calculate the molarity as follows.

Molarity = $\frac{0.005 \times 10^{-3}}{112.41} mol/L$

= $4.45 \times 10^{-8}$ M

Equation for the reaction is as follows.

$Cd(OH)_{2} \rightleftharpoons Cd^{2+} + 2OH^{-}$

$K_{sp} = [Cd^{2+}][OH^{-}]^{2}]$

$2 \times 10^{-34} = 4.45 \times 10^{-8} \times [OH^{-}]^{2}$

$[OH^{-}] = 6.7 \times 10^{-4}$ M

Also,

$[H^{+}] = \frac{10^{-14}}{[OH^{-}]}$

= $\frac{10^{-14}}{6.7 \times 10^{-4}}$

= $1.49 \times 10^{-11} M$

Relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

= $-log (1.49 \times 10^{-11} M)$

= 10.82

Thus, we can conclude that a minimum pH of 10.82 is necessary to reduce the dissolved cadmium ion concentration to the standard.

4 0

3 years ago

Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.

igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, $[\text{H}^{+}] = 10^{-\text{pH}}$ , where $[\text{H}^{+}]$ is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, $[\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}$ .

$[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w$ , where $[\text{OH}^{-}]$ the concentration of hydroxide ions and $\text{K}_w$ is the dissociation constant of water.

$\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3}$ at 0.10 MPa and 25 °C. As a result, $[\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}$ .

5 0

3 years ago

Slove this fill in blanks

bagirrra123 [75]

Answer:

1) Heterogeneous mixture

2). homogeneous mixture

3) water is solvent and sugar is solute

4). sublimation process

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Ghella [55]

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3 years ago

What is albert einstein's nationality?

levacccp [35]

German,Prussian,Weimar,American,Swiss

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