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snow_lady [41]
2 years ago
15

Write the first and second ionization equations for H2SeO3 please.

Chemistry
1 answer:
IRISSAK [1]2 years ago
3 0
As a diprotic acid, the H₂SeO₃ can ionize by step. First step is H₂SeO₃ =(reversible reaction) H⁺ + HSeO₃⁻. And second step is HSeO₃⁻ =(reversible reaction) H⁺ +SeO₃ ²⁻.
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A sample of methane gas occupies 4.50 gallons at a temperature of 80.0 F. If the pressure is held constant, what will be the vol
Marat540 [252]

Answer:

21.19 L or 5.6 gallons

Explanation:

Data Given

initial volume V1 = 4.50 gallons

convert volume from gallons to L

                               1 gallon = 3.78541 L

                               4. 50 gallon = 3.785 L x 4.50

So,                        

initial volume V1 =  17.03 L

final Volume V2 = ?

initial Temperature T1  = 80° F

convert Temperature to Kelvin

                              T1 = ( 80° F -32) / 1.8 +273

                               T1 = 26.7° C + 273 = 299.7 K

final Temperature T2 = 100° C

convert Temperature to Kelvin

                                  T2 = 100° C + 273 = 373 K

Solution:

This problem will be solved by using charles' law equation at constant pressure.

The formula used

                      V1 / T1 = V2 / T2

As we have to find out volume, so rearrange the above equation

                      V2 = V1 x T2 / T1

Put value from the data given and conversion information in above equation

V2 =  17.03 L x 373 K / 299.7 K

V2 =  21. 19 L

So the final volume of Methane gas = 21.19 L

Or for Volume in gallons

1 L = 0.26

21.19 x 0.264 = 5.6 gallons

7 0
3 years ago
The pentose phosphate pathway (PPP) is localized to the cytosol.
DIA [1.3K]

Answer: The pentose phosphate pathway (PPP) is localized to the cytosol because fatty acid synthesis uses the NADPH generated by the PPP.

Explanation:

The pentose phosphate pathway is mainly catabolic and provides an alternative glucose oxidizing pathway for the generation of NADPH that is required for reductive biosynthetic reactions such as those of cholesterol biosynthesis, bile acid synthesis, steroid hormone biosynthesis, and fatty acid synthesis.

Fatty acid biosynthesis occurs in the cytosol and requires the reducing equivalent NADPH in large amounts. <em>The main source of generating NADPH in animal cells, the pentose phosphate pathway is therefore, localized in the cytosol in order to furnish a strongly reducing environment for fatty acid biosynthesis to proceed.</em>

5 0
3 years ago
Water’s freezing point is 32 degrees F = _____ Celcius = _____ Kelvin
lutik1710 [3]

Waters freezing point in Celsius is 0 and 273.15 Kelvin (or 273 rounded to a whole number.

8 0
2 years ago
Heating a carboxylic acid with a primary amine forms water along with what organic product? OA) A secondary amide OB) A primary
Bezzdna [24]

Answer:

A) secondary amide

Explanation:

When carboxylic acid reacts with a primary amine, a condensation reaction takes place with the elimination of a water molecule .

For example, ethanol reacts with methylamine which is a primary amine gives N-Methylacetamide and a water molecule as:

CH_3COOH+NH_2CH_3\rightarrow CH_3-CONH-CH_3+H_2O

The bond formed which is

  O

   ||

-- C  ---NH ---

is known as secondary amide group as only one hydrogen is attached to nitrogen atom in the amide bond.

5 0
3 years ago
One of the chair conformers of cis-1,3-dimethylcyclohexane is 5.4 kcal/mol less stable than the other. How much steric strain do
Karolina [17]

Answer:

See explanation

Explanation:

the Cis structure, we can have two possibilities. The methyl groups can go both in <u>axial positions</u> or both in <u>equatorial positions</u>. We have to remember that cis it means <u>"same orientation"</u>, so in the axial positions, both methyl groups go up. (Both have the same orientation). In the equatorial positions, both groups go down.

In the axial positions, we will have <u>more steric hindrance</u> because the groups are close to each other. Therefore, we will have <u>more energy</u> and the structure will be <u>less stable</u>. In the equatorial positions, we <u>dont have any steric hindrances</u>, so we will have <u>less energy and more stability</u>.

See figure 1

I hope it helps!

7 0
3 years ago
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