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3 years ago

Julie works 7.65$ per hour. How many hours doe sit take to get Julie 24.48?

2 answers:

7 0

Julie makes $7.65 for 1 hour. We know she earned $24.48 so how many hours did she work to earn that? you could set it up like this

1hr = X (hrs)
$7.65 $24.48 (money earned) now cross multipy

7.65 * x = 1*24.48
7.65x=24.48 (now we want x alone)

7.65x=24.48 (you must divide both sides by 7.65 to get x alone)
7.65 7.65
now any number divided by itself is 1 so
1x is automatically written like this

x=24.48
7.65 now divide 24.48 by 7.65 to get the answer
x=3.2 hours that's your answer. She worked 3.2 hours to earn $24.48

siniylev [52]3 years ago

5 0

24.48/7.65=3.2
It takes her 3.2 hours

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Ivan has $1098 worth of $12 and $14 stock shares. The number of $14 shares is seven more than

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Number of 12$ Shares? 25

Number of 14$ Shares? 57

Step-by-step explanation:

Let x = number of $12 shares.

Let y = number of $14 shares.

"Ivan has $1098 worth of $12 and $14 stock shares."
12x + 14y = 1098

The number of $14 shares is seven more than twice the number of $12 shares.

y = 2x + 7

We have a system of equations.

12x + 14y = 1098

y = 2x + 7

We can use the substitution method since the second equation is already solved for y. Substitute 2x + 7 for y in the first equation.

12x + 14(2x + 7) = 1098

12x + 28x + 98 = 1098

40x = 1000

x = 25

There are 25 $12 shares.

y = 2x + 7 = 2(25) + 7 = 57

There are 57 $14 shares.

Check:

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3 years ago

Read 2 more answers

A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res

Alexus [3.1K]

Answer:

Step-by-step explanation:

Hello!

So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:

X: "Lifetime of one shoe pair of the new model"

Applying CLT:

X[bar]≈N(μ;σ²/n)

Known values:

n= 30 shoe pairs

x[bar]: 17 months

S= 5.5 months

Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:

H₀:μ=15

H₁:μ≠15

The significance level for the test is given: α: 0.05

Your critical region will be two-tailed:

$Z_{\alpha /2} = Z_{0.025}= -1.96$

$Z_{1-\alpha /2} = Z_{0.975}= 1.96$

So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96

Now you calculate your observed Z-value

Z=x[bar]-μ ⇒ Z= 17-15 = 1.99

σ/√n 5.5/√30

Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.

I hope you have a SUPER day!

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3 years ago