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3 years ago

The Moon orbits the Earth once in about _______.

Physics

2 answers:

ivann1987 [24]3 years ago

8 0

Answer:

28 days

Explanation:

I did the question and got it right.

Bas_tet [7]3 years ago

7 0

Answer:

The moon orbits the Earth once in about 27.332 days.

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A child tugs on a rope attached to a 0.62 kg toy with a horizontal force of 16.3 N. A puppy pulls the toy in the opposite direct

sattari [20]

Answer:

$a=51.77\ m/s^2$

Explanation:

Given that,

The mass of a toy, m = 0.62 kg

Force with which a child pull the toy = 16.3 N

The force with which the toy pulled in the opposite direction = -15.8 N

We need to find the acceleration of the toy. Let F be the net force acting on the toy. It is equal to :

F = 16.3 N - (-15.8 N)

= 32.1 N

Let a be the acceleration of the toy. Using Newton' second law of motion to find it.

F = ma

$a=\dfrac{F}{m}\\\\a=\dfrac{32.1}{0.62}\\\\a=51.77\ m/s^2$

So, the acceleration of the toy is $51.77\ m/s^2$ .

5 0

3 years ago

In which of the following cases is work being done on an object? Question 2 options: Pulling a trailer up a hill Carrying a box

Taya2010 [7]

Work is done when a force acts on an object AND the object moves in the direction of the force.

-- <em>Pulling a trailer up a hill. YES. </em> The trailer is moving in the direction of the pulling force.

-- Carrying a box down a corridor. No. The box is not moving in the direction of gravity (down) OR in the direction of your arm (down the corridor).

-- Suspending a heavy weight with a strong chain, No. There's a force (gravity) acting on the weight, but the weight is not moving at all.

-- Pushing against a locked door. No. There's a force (your muscles) acting on the door, but he door is not moving at all.

4 0

4 years ago

Read 2 more answers

A4.0 kg object is moving with speed 2.0 m/s. A 1.0 kg object is moving with speed 4.0 m/s. Both objects encounter the same const

Evgesh-ka [11]

Answer:

Both objects travel the same distance.

Explanation:

Given that,

Mass of first object = 4.0 kg

Speed of first object = 2.0 m/s

Mass of second object = 1.0 kg

Speed of second object = 4.0 m/s

We need to calculate the stopping distance

For first particle

Using equation of motion

$v^2=u^2+2as$

Where, v = final velocity

u = initial velocity

s = distance

Put the value in the equation

$0= u^2-2as_{1}$

$s_{1}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{1}=\dfrac{8}{F}$

Now, For second object

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$0= u^2-2as_{2}$

$s_{2}=\dfrac{u^2}{2a}$ ....(I)

Using newton law

$F = ma$

$a=\dfrac{F}{m}$

Now, put the value of a in equation (I)

$s_{2}=\dfrac{8}{F}$

Hence, Both objects travel the same distance.

6 0

3 years ago

ILL GIVE BRAINLIEST AND 5 POINT STAR RATING!!!! Which cultural region of the United States has the most Native American influenc

avanturin [10]

Answer:

The answer is 4, the west.

7 0

3 years ago

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A city bus travels along its route from Jackson Street 8

wel

Answer:21km

Explanation:13km+8km=21km

6 0

4 years ago