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Vitek1552 [10]
3 years ago
6

Find the work done lifting a 290-pound weight 28 feet in the air.

Physics
2 answers:
dusya [7]3 years ago
8 0
Hello there.

<span>Find the work done lifting a 290-pound weight 28 feet in the air.

</span><span>d.
8,120 foot-pounds</span>
Nataly [62]3 years ago
6 0
The answer is d.8,120 foot-pounds
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A plane took 7 hours to travel 2020 km. For the first 4 hours,
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Answer:

-6.6 km/h

Explanation:

In 7hr plane travelled 2020km;

For the first 4hr the average speed was 310km/h;

d=st, s=d/t;

Distance covered in first 4h is d = 310km/h×4h = 1240km;

See the image attached for further solution

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3 years ago
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How long does it take a wheel that is rotating at 33.3 rpm to speed up to 78.0 rpm if it has an angular acceleration of 2.15 rad
Rzqust [24]

initial angular speed is given by 33.3 rpm

w_0 = 2\pi \frac{33.3}{60}

w_0 = 3.49 rad/s

final angular speed is given by 78 rpm

w_f = 2\pi \frac{78}{60}

w_f = 8.17 rad/s

now by using kinematics we will have

w_f = w_0 + \alpha * t

8.17 = 3.49 + 2.15 * t

t = 2.17 seconds

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3 years ago
Why don't we see objects in the universe colliding or moving towards each other due to gravitational force?​
Citrus2011 [14]

Answer:

the objects in the universe are evenly placed. This means that a celestial object's gravity may not be able to attract another object. Another reason may be that the stars in solar systems act as points of equilibrium for the planets in the system. Take for example the sun. It maintains the position of the planets in the system and likewise the earth maintains the position of the moon. You can picture it as evenly placed atoms in matter and the subsequent electrons held by the nucleus

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3 years ago
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In four-seater countries, temperature drops below 0 ° C during peak winter. Why only the frozen surface of the water instead of
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The surface is the main area that is exposed to the cold.
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3 years ago
You have designed and constructed a solenoid to produce a magnetic field equal in magnitude to that of the Earth (5.0 10-5 T). I
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Answer:

I = 0.03637 A

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So, number of turns per unit length :

n=\frac{N}{L}

n=\frac{350\: turns}{0.32 m}

n=1093.75 \: turns \: per \: meter

If current is I , then magnetic field is given by

B = \mu_{0} \times n \times I

Also,

I = \frac{B}{\mu_{0} \times n}

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I = \frac{5.0 \times 10^{-5}}{4 \pi \times 10^{-7} \times 1093.75} A

I = 0.03637 A

The current will be I = 0.03637 A

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