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Vitek1552 [10]
3 years ago
6

Find the work done lifting a 290-pound weight 28 feet in the air.

Physics
2 answers:
dusya [7]3 years ago
8 0
Hello there.

<span>Find the work done lifting a 290-pound weight 28 feet in the air.

</span><span>d.
8,120 foot-pounds</span>
Nataly [62]3 years ago
6 0
The answer is d.8,120 foot-pounds
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What condition is most necessary to build a glacier?
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3 years ago
If a 2 cm vector represents speed, and 1 cm equals 5 m/s, how fast is the represented
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6 0
3 years ago
Two identical strings, of identical lengths of 2.00 m and linear mass density of μ=0.0065kg/m, are fixed on both ends. String A
kolezko [41]

Answer:

beat frequency = 13.87 Hz

Explanation:

given data

lengths l = 2.00 m

linear mass density μ = 0.0065 kg/m

String A is under a tension T1 = 120.00 N

String B is under a tension T2 = 130.00 N

n = 10 mode

to find out

beat frequency

solution

we know here that length L is

L = n × \frac{ \lambda }{2}      ........1

so  λ = \frac{2L}{10}  

and velocity is express as

V = \sqrt{\frac{T}{\mu } }    .................2

so

frequency for string A = f1 = \frac{V1}{\lambda}

f1 = \frac{\sqrt{\frac{T}{\mu } }}{\frac{2L}{10}}

f1 = \frac{10}{2L} \sqrt{\frac{T1}{\mu } }      

and

f2 = \frac{10}{2L} \sqrt{\frac{T2}{\mu } }

so

beat frequency is = f2 - f1

put here value

beat frequency = \frac{10}{2*2} \sqrt{\frac{130}{0.0065}}  - \frac{10}{2*2} \sqrt{\frac{120}{0.0065} }

beat frequency = 13.87 Hz

6 0
4 years ago
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