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Vitek1552 [10]
3 years ago
6

Find the work done lifting a 290-pound weight 28 feet in the air.

Physics
2 answers:
dusya [7]3 years ago
8 0
Hello there.

<span>Find the work done lifting a 290-pound weight 28 feet in the air.

</span><span>d.
8,120 foot-pounds</span>
Nataly [62]3 years ago
6 0
The answer is d.8,120 foot-pounds
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Answer:

5.65 m/s²

Explanation:

We'll begin by calculating the mass of PJ when in San Diego (i.e Earth). This can be obtained as follow:

Weight of PJ on Earth (Wₑ) = 545 N

Acceleration due to gravity (g) on Earth (gₑ) = 10 m/s²

Mass of PJ on Earth (mₑ) =.?

Wₑ = mₑ × gₑ

545 = mₑ × 10

Divide both side by 10

mₑ = 545 / 10

mₑ = 54.5 Kg

Thus, the mass of PJ on San Diego (i.e Earth) is 54.5 Kg

Finally, we shall determine the acceleration due to gravity of planet Koja. This can be obtained as follow:

Weight of PJ on Koja (Wₖ) = 308 N

Mass of PJ on Koja (mₖ) = mass of PJ on Earth (mₑ) because mass is constant irrespective of location.

Mass of PJ on Earth (mₑ) = 54.5 Kg

Mass of PJ on Koja (mₖ) = 54.5 Kg

Acceleration due to gravity of on Koja (gₖ) =?

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308 = 54.5 × gₖ

Divide both side by 54.5

gₖ = 308 / 54.5

gₖ = 5.65 m/s²

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Which of the following describes the bending of light due to a change in its speed?
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Explanation:

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