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Arada [10]
3 years ago
12

A gas expands from an initial volume of 0.040 m^3 and an initial pressure of 210 kPa to a final volume of 0.065 m^3 while its te

mperature is kept constant. How much work is done by the system?
Physics
1 answer:
USPshnik [31]3 years ago
7 0

Answer:

286

Explanation:

p1v1/T1=p2v2/T2

then subtitude your values

T2=760*0.65*273/210*0.040

T2=135/8.4=16+273=289

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zloy xaker [14]

Answer:

The maximum kinetic energy is 100 j.    

Explanation:

<h3>The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum. </h3>

4 0
3 years ago
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A 2500-lb vehicle has a drag coefficient of 0.35 and a frontal area of 20 ft2. What is the minimum tractive effort required for
emmasim [6.3K]

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i put this in the calculator and my answer is 600. hope this helps

Explanation:

4 0
4 years ago
A concave mirror always forms a virtual image of a real object. O True O False
kifflom [539]

Answer:

The given statement is false.

Explanation:

The spherical mirrors are the mirror that are a part of a sphere. Concave and convex mirrors are two types of spherical mirrors.

A concave mirror always forms real and inverted image. A convex mirror forms real and virtual images.

For concave mirror, the value of magnification is less that 1. Also, the focal length is negative for concave mirrors.

So, the given statement is false as a concave mirror always forms a real and inverted image. Hence, this is the required solution.

4 0
4 years ago
What are some examples and non-examples of volume
Jlenok [28]

Answer:

Explanation:

Some correct non-examples are: A glass half-empty; Anything in two dimensions; The amount that covers something.

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3 years ago
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A truck on a straight road starts from rest, accelerating at 2.00m/s^2 until it reaches a speed of 20.0m/s. Then the truck trave
Dennis_Churaev [7]

Answer:

Explanation:

a )

Time to reach the speed of 20 m/s with an acceleration of 2 m/s² can be calculated as follows .

v = u + a t

20 = 0 + 2 t

t = 20 /2 = 10 s .

Total time = 10 s + 20 s + 5 s = 35 s .

b) Average velocity = Total distance travelled / total time

Distance travelled in first 10 s

S₁ = ut + 1/2 a t²

= 0 + .5 x 2 x 10²

= 100 m

Distance travelled in next 20 s

S₂= 20s x 20 m/s  = 400 m

Distance travelled in last 5 s .

deceleration in last 5 s

v = u + at

0 = 20 m/s + a x 5

a = - 4 m/s²

v² = u² - 2 a s

0 = (20 m/s)² - 2 x 4 m/s² x s

s = 50 m

S₃ = 50 m

Total distance = S₁ + S₂ + S₃

= 100 m + 400 m + 50 m

= 550 m .

Average velocity = 550 m / 35 s

= 15.71 m /s .

3 0
3 years ago
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