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3 years ago

PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS HELP

Physics

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

So, instead of fossil fuels, the magnetic field thats creatd by electrified coils in the guideway walls, and on the track combine to propel the train. Just think of it as playing with magnets. The opposite attract while if you put norh to north or south to south, they will push away from each ther. This is just the basic principle of electromagnetic propulsion

Explanation:

rodikova [14]3 years ago

7 0

Answer:

C motors

Electric motors use the forces produced by magnetic fields to produce a turning motion. If you put a length of wire in a magnetic field and pass a DC current through it (such as from a battery), the wire will move. This is called the motor effect.

To make a simple DC motor, you need:

two bar magnets

a coil of wire wrapped around something to support it

an axle for the coil of wire to spin around

two half rings (‘split rings’)

hope this helps

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A force of 100 N acts upward. Resolve this force into 2 components; one that acts 30º north of west and one that acts 60º north

GrogVix [38]

To resolve these forces we have to make use of the sines and cosines.

To resolve this force in 30 degree north of west, the answer will be

100*sin(30)

The answer will be 50N

Now to resolve the force acting 60 degree north of east

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sveta [45]

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3 years ago

Which of the following is the volume of the shaded in Of the sphere?

marysya [2.9K]

Answer:

The correct option is;

πR³(2/3 + (1/3)cos³θ - cosθ)

Explanation:

The volume of a segment of a sphere is given by the relation;

$V = \pi \cdot h^2 \cdot \left (R - \dfrac{h}{3} \right)$

We note that h = R - R·cos(θ)

Therefore by substituting the value of h in the equation of a segment of a sphere, we have;

$V = \pi \cdot \left (R - R\cdot cos(\theta) \right ) ^2 \cdot \left (R - \dfrac{\left (R - R\cdot cos(\theta) \right )}{3} \right)$

Which gives;

$\dfrac{R^3\cdot \pi \cdot cos^3 (\theta) -3 \cdot R^3 \cdot\pi \cdot cos (\theta) + 2 \cdot R^3 \cdot \pi}{3}$

$R^3\cdot \pi \cdot \left (\dfrac{cos^3 (\theta) -3 \cdot cos (\theta) + 2 }{3} \right )$

$R^3\cdot \pi \cdot \left (\dfrac{cos^3 (\theta) + 2 }{3} - cos (\theta) \right )$

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Therefore, the correct option is πR³(2/3 + (1/3)cos³θ - cosθ).

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bagirrra123 [75]

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