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babymother [125]
3 years ago
10

PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS HELP

Physics
2 answers:
PIT_PIT [208]3 years ago
7 0

Answer:

So, instead of fossil fuels, the magnetic field thats creatd by electrified coils in the guideway walls, and on the track combine to propel the train. Just think of it as playing with magnets. The opposite attract while if you put norh to north or south to south, they will push away from each ther. This is just the basic principle of electromagnetic propulsion

Explanation:

rodikova [14]3 years ago
7 0

Answer:

C motors

Electric motors use the forces produced by magnetic fields to produce a turning motion. If you put a length of wire in a magnetic field and pass a DC current through it (such as from a battery), the wire will move. This is called the motor effect.

To make a simple DC motor, you need:

two bar magnets

a coil of wire wrapped around something to support it

an axle for the coil of wire to spin around

two half rings (‘split rings’)

hope this helps

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Describe the changes of motion when marble is moved from one viewpoint to another.
slavikrds [6]

Answer:

Explanation:

according to Newton First Law of Motion (Law of Inertia); An object at rest will stay at rest, forever, as long as nothing pushes or pulls on it. An object in motion will stay in motion, traveling in a straight line, forever, until something pushes or pulls on it.

the marble will move in a straight line

5 0
3 years ago
Trivia Time!! At what velocity does light move?
Maslowich

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

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2 years ago
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HELP PLEASE I OWE YOU GUYS
Mekhanik [1.2K]

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no se ingles nu mames

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3 years ago
With which of the following is the weak nuclear force associated
BaLLatris [955]
You need to post a picture bro
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2 years ago
A particle's trajectory is described by x = (0.5t^3-2t^2) meters and y = (0.5t^2-2t), where time is in seconds. What is the part
mestny [16]

Differentiate the components of position to get the corresponding components of velocity :

v_x = \dfrac{\mathrm dx}{\mathrm dt} = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) t^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)t

v_y = \dfrac{\mathrm dy}{\mathrm dt} = \left(1\dfrac{\rm m}{\mathrm s^2}\right)t-2\dfrac{\rm m}{\rm s}

At <em>t</em> = 5.0 s, the particle has velocity

v_x = \left(1.5\dfrac{\rm m}{\mathrm s^3}\right) (5.0\,\mathrm s)^2 - \left(4\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s) = 17.5\dfrac{\rm m}{\rm s}

v_y = \left(1\dfrac{\rm m}{\mathrm s^2}\right)(5.0\,\mathrm s)-2\dfrac{\rm m}{\rm s} = 3.0\dfrac{\rm m}{\rm s}

The speed at this time is the magnitude of the velocity :

\sqrt{{v_x}^2 + {v_y}^2} \approx \boxed{17.8\dfrac{\rm m}{\rm s}}

The direction of motion at this time is the angle \theta that the velocity vector makes with the positive <em>x</em>-axis, such that

\tan(\theta) = \dfrac{3.0\frac{\rm m}{\rm s}}{17.5\frac{\rm m}{\rm s}} \implies \theta = \tan^{-1}\left(\dfrac{3.0}{17.5}\right) \approx \boxed{9.73^\circ}

4 0
2 years ago
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