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sergiy2304 [10]
3 years ago
10

I must be present in a compound for it considered organic

Chemistry
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

Carbon

Explanation:

Organic compounds must contain carbon. They also usually contain hydrogen,  oxygen, and often nitrogen and other compounds such as phosphorus.

Nearly all organic compounds contain carbon-hydrogen bonds.

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What is the conjugate base<br> of H2O?
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A conjugate acid, is a species formed by the reception of a proton (H+) by a base—in other words, it is a base with a hydrogen ion added to it.

OH- is the conjugate base of H2O..

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3 years ago
A material was cooled from 100°C to 40°C. What is the temperature change?
vazorg [7]
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Just subtract
8 0
3 years ago
1. Pewien tlenek azotu o masie cząsteczkowej 108 u zawiera 74,07% tlenu. Wykonaj stosowne obliczenia i napisz wzór sumaryczny te
love history [14]

Answer:

1. Stąd empiryczny wzór substancji to N₂O₅

2. W związku z tym ilość w gramach chlorku sodu NaCl is 114,4 g.

Explanation:

1. Mamy tutaj;

Masa molowa tlenku azotu = 108u

Masa azotu = 14,0067u

Masa tlenu = 15,999 u

74,07% masy tlenku azotu to tlen

Dlatego masa obecnego tlenu = 108 × 74,07 / 100 = 79,9956 u

Masa obecnego azotu = 108 - 79,9956 = 28,0044u

Liczba moli tlenu = 79,9956 / 15,999 = 5,00003 ≈ 5

Liczba moli azotu = 28,0044 / 14,0067 = 1,99935 ≈ 2

Stąd empiryczny wzór substancji to N₂O₅.

2. Kiedy sód reaguje z chlorem, mamy;

2Na (s) + Cl₂ (g) → 2NaCl (s)

Dlatego 2 mole sodu Na reaguje z 1 molem chloru gazowego Cl₂, z wytworzeniem 2 moli chlorku sodu NaCl

W związku z tym 1 mol sodu Na reaguje z 1/2 molem chloru gazowego Cl₂ z wytworzeniem 1 mola chlorku sodu NaCl

Masa Na obecnego w reakcji = 45 g

Masa molowa sodu = 22,989769u

Liczbę moli sodu w 45 g sodu podano w następujący sposób;

Liczba \, \, moli \, \, Na= \frac{Mass \, of \, Na}{Molowy \, masa \, z \, Na} = \frac{45}{22.989769} = 1.96 \, mole

Z czego 1,96 moli sodu Na reaguje z 1/2 × 1,96 mola chloru gazowego Cl₂ z wytworzeniem 1,96 mola chlorku sodu NaCl

Masa molowa NaCl = 58,44 g / mol

Dlatego masa NaCl = liczba moli NaCl × masa molowa NaCl

Masa NaCl = 1,96 × 58,44 = 114,39001 g ≈ 114,4 g

W związku z tym ilość w gramach chlorku sodu NaCl = 114,4 g.

4 0
3 years ago
Hello!! I need help please! Please explain how I can identify a percipitate in a reaction! I need help with chemistry ha
antiseptic1488 [7]
Generally speaking a precipitate is something that will form as a result of the reaction.  It generally is a solid material.

Sodium and nitrates are soluble so Calcium Phosphate would precipitate out....


5 0
3 years ago
I REALLY NEED YOUR HELPPPPPP!!!!!!!!!!!!!!!!!!!!when the boy was skating,kinetic energy was ______and thermal energy was _______
77julia77 [94]

Answer:high,low,decreasing,increasing,low,high,potential,kinetic

Explanation:

4 0
3 years ago
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