Answer:
c or d I think but I'm not completely shure
The reaction of sodium bromide with chlorine gas is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
<h3>What is sodium bromide?</h3>
Sodium bromide is an inorganic compound, white, crystalline with high melting point.
The reaction between halogens is redox reaction
Oxidation – 2Br⁻ ? Br₂ + 2e⁻ loss of electron.
Reduction – Cl₂ + 2e⁻ ? 2Cl⁻ gains of electron.
Thus, the correct option is Cl₂(aq) + 2Na + 2Br? 2Na + 2Cl⁻ + Br²(aq).
Learn more about sodium bromide
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Answer:
(b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen.
Explanation:
The law of definite proportion states that a gen chemical compound always contains its constituent elements in a fixed ratio by mass, independent on the method of preparation.
The molar mass of Nitrogen and Oxygen would always remain the same, allowing for exact reactant masses (or mole ratio) irrespective of the given amount of sample.
Answer: 0.0944 gram of H2
Explanation:
Raising the T from 25 C (298 K) to 700 C (973 K) increases the pressure of each gas by:
2.0 atm x (973 K / 298 K) = 6.53 atm
Where
Kc = Kp because the moles of product equals the moles of reactants.
At equilibriuim, the amounts are
P(H2) = 6.53 - x
P(CO2) = 6.53 - x
P(H2O) = x
P(CO) = x
Kc = Kp = .534 = (x)(x) / [(6.53 - x)(6.53 - x)]
Take the square root of each side
(.534)^0.5 = x / (6.53 - x)
x = 0.731 (6.53 - x)
x = 4.77 - 0.731x
1.731x = 4.77
x = 4.77 / 1.731 = 2.76 atm
P(H2) at equilibriuim = 6.53 - 2.76 = 3.77 atm
P(CO2) at equilibrium = 6.53 - 2.76 = 3.77 atm
PV = nRT
n = PV/RT = [(3.77 atm)(1.00 L)] / [(0.08206 L atm/K mol)(973 K)] = 0.0472 mol H2
0.0472 mol H2 x (2.00 g / 1.00 mol) = 0.0944 g
