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kotegsom [21]
3 years ago
14

How are atomic mass and mass number similar

Chemistry
1 answer:
omeli [17]3 years ago
4 0
There is a difference between the meanings of the chemistry terms atomic mass and mass number. One is the average weight of an element and the other is the total number of nucleons in the atom's nucleus. ... The mass number is a count of the total number of protons and neutrons in an atom's nucleus.
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Rhodium crystallizes in a face-centered cubic unit cell. The radius of a rhodium atom is 135 pm. Determine the density of rhodiu
Deffense [45]

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

r = \dfrac{a}{2\sqrt{2}}

where;

a = edge length.

Making "a" the subject of the formula:

a = 2 \sqrt{2} \times r

a = 2 \times 1.414 \times 135 \ pm

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

mass\  of\ atom =\dfrac{ atomic \ mass}{Avogadro  \  number}

mass\  of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4

mass of unit cell = 6.83380375 × 10⁻²² g

Density  \ of  \ unit \  cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}

Density of unit cell ( rhodium) = 12.279 g/cm³

3 0
2 years ago
Which of the following objects does not decompose?
Anettt [7]
B) Plastic Water Bottle
6 0
3 years ago
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If a horse is moving and then come to a stop is the horse accelerating or decelerating
quester [9]

Answer:

decelerating hope this helps❤️

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represent rutheniums first 36 electrons using the chemical symbol for krypton written inside the brackets
kirza4 [7]

Answer:

[kr] hd^75s^1

Explanation:

7 0
3 years ago
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How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL
Sedaia [141]

Answer:

209.98 g of NaOH

Explanation:

We are given;

  • Volume of HCl as 3 L
  • Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a  balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

                             = 1.75 M × 3 L

                             = 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

                          = 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

                        = 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

6 0
3 years ago
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