<h3>Answer:</h3>
The lowest boiling point is of n-Butane because it only experiences London Dispersion Forces between molecules.
<h3>Explanation:</h3>
Lets take start with the melting point of both compounds.
n-Butane = - 140 °C
Trimethylamine = - 117 °C
Intermolecular Forces in n-Butane:
As we know n-Butane is made up of Carbon and Hydrogen atoms only bonded via single covalent bonds. The electronegativity difference between C and C atoms is zero while, that between C and H atoms is 0.35 which is less than 0.4. Hence, the bonds in n-Butane are purely non polar in nature. Therefore, only London Dispersion Forces are found in n-Butane which are considered as the weakest intermolecular interactions.
Intermolecular Forces in Trimethylamine:
Trimethylamine (a tertiary amine) is made up of Nitrogen, Carbon and Hydrogen atoms bonded via single covalent bonds. The electronegativity difference between N and C atoms is 0.49 which is greater than 0.4. Hence, the C-N bond is polar in nature. Therefore, Dipole-Dipole interactions will be formed along with London Dispersion Forces which are stronger than Dispersion Forces. Therefore, due to Dipole-Dipole interactions Trimethylamine will have greater melting point than n-Butane.
They are the chemical symbol like the ones on the periodic table
Answer:
3
Explanation:
Atoms are made of 3 parts.
- The protons and Neutrons form together creating a sun, or nucleus at the center
- The electrons orbit this sun like planets.
The element with Th is Thorium. It is a metallic chemical element that when exposed to air, hardens.
Answer:
pOH = 5
pH = 9 → Solution is basic
Explanation:
We need to know that:
pH + pOH = 14
< 7 ⇔ pH = 7 ⇔ > 7
Acidic Neutral Basic
pOH = - log [OH⁻] → - log 9.8×10⁻⁶ = 5.00
pOH = 5
pH = 14 - 5 = 9
Answer:
Explanation:
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