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-BARSIC- [3]
2 years ago
8

How many grams of vanadium, V, would contain the same number of atoms as 32.066 g of sulfur, S?

Chemistry
1 answer:
ollegr [7]2 years ago
7 0
For there to be an equal number of atoms, there must be an equal number of moles.

Moles = mass / Mr

Moles of Sulfur = 32.066 / 32.066
= 1 mole

Mass of one mole of vanadium = 50.942 grams

50.942 grams of vanadium will contain the same number of atoms as 32.066 grams of sulfur.
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How many moles of calcium, Ca, are in 5.00 g of calcium?
Rom4ik [11]
<h3>Answer:</h3>

0.125 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

5.00 g Ca

<u>Step 2: Identify Conversions</u>

Molar mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 5.00 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})
  2. Multiply:                             \displaystyle 0.12475 \ mol \ Ca

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.12475 mol Ca ≈ 0.125 mol Ca

3 0
2 years ago
A solution was prepared by mixing 50.00 ml of 0.100 M of HNO3 and 100.00 ml of 0.200 M HNO3. Calculate the molarity of the final
valentina_108 [34]

Answer:

The molarity of this final solution is 0.167 M

Explanation:

Step 1: Data given

Volume of a 0.100 M HNO3 solution = 50.0 mL

Volume of a 0.200 M HNO3 = 100.0 mL

Step 2: Calculate moles

The final molarity must lie between 0.1M and 0.2M  

Moles = molarity * volume

Moles HNO3 in 50mL of a 0.100M solution = 0.05 L *0.100 M = 0.005 mol

Moles HNO3 in 100mL of a 0.200M solution = 0.100 L*0.200 = 0.020mol

total moles = 0.005+0.020 = 0.025 moles in 150mL solution = 0.150L

Step 3: Calculate molarity of final solution

Molarity = mol / volume

Molarity 0.025 moles /0.150  L

Molarity = 0.167M

The molarity of this final solution is 0.167 M

4 0
3 years ago
Read the sentence.
elena-s [515]

Answer:

B

It defines the concept of conservation of matter.

Explanation:

8 0
2 years ago
Which does not describe the relationship between the nucleus and the electron cloud of an atom?
rusak2 [61]
I think the correct answer among the choices is option B. The statement which does not describe the relationship between the nucleus and the electron cloud of an atom will be that the <span> masses of the nucleus and electron cloud are balanced.</span>
4 0
2 years ago
Read 2 more answers
The density of an aqueous solution containing 10.0 percent of ethanol (C2H5OH) by mass is 0.984 g/mL. (a) Calculate the molality
Mrrafil [7]

Answer:

a. 2.41 molal

b. 0.21 M

c. 58.5 mL

Explanation:

First of all let's think the data 10 % by mass, which means, that 10 grams from the solute is contained in 100 g of this solution.

So If we know solution density, we can get its volume.

Solution density = Solution mass / Solution volume

0.984 g/ml = 100 g / Solution volume

Solution volume = 100 g/ 0.984g/ml

Volume = 101.6 mL

As we have 10 g of solute, 100 g of solution, we have 90 g of solvent.

Solute mass + Solvent mass = Solution mass

How many moles do we have in 10 g of ethanol?

Molar mass of ethanol: 46.07 g/m

Mass / molar mass = Moles

10 g/ 46.07 g/m = 0.217 mol

This quantity is in 90 g of solvent and 101.6 mL of solution. For molality and molarity, we should use a rule of three to find out the moles in 1 kg of solvent and 1 L of solution.

1 L = 1000 mL

1kg = 1000 g

<u>Molality</u>

90 g _____ 0.217 moles

1000 g _____ (1000 . 0.217)/ 10 = 2.41 molal

Molarity

101.6 mL ___ 0.217 moles

1000 mL ____  (1000 . 0.217) / 101.6 = 0.21 M

What volume of the solution would contain 0.125 mole of ethanol?. Let's think a new rule of three.

0.217 moles of solute ___ are in __ 101.6 mL of solution

0.125 moles of solute___ are in (0.125 . 101.6)/0.217 = 58.5 mL

6 0
2 years ago
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