How many grams of vanadium, V, would contain the same number of atoms as 32.066 g of sulfur, S?
1 answer:
For there to be an equal number of atoms, there must be an equal number of moles.
Moles = mass / Mr
Moles of Sulfur = 32.066 / 32.066
= 1 mole
Mass of one mole of vanadium = 50.942 grams
50.942 grams of vanadium will contain the same number of atoms as 32.066 grams of sulfur.
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