How many grams of vanadium, V, would contain the same number of atoms as 32.066 g of sulfur, S?

1 answer:

7 0

For there to be an equal number of atoms, there must be an equal number of moles.

Moles = mass / Mr

Moles of Sulfur = 32.066 / 32.066
= 1 mole

Mass of one mole of vanadium = 50.942 grams

50.942 grams of vanadium will contain the same number of atoms as 32.066 grams of sulfur.

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