Answer:
3MnO₄⁻ + 24H⁺ + 5Au → 5Au³⁺ + 3Mn²⁺ + 12H₂O.
Explanation:
- KMnO₄ is strong oxidizing agent which is reduced and oxidizes Au according to the two-half reactions:
The oxidation reaction: Au → Au³⁺ + 3e.
The reduction reaction: MnO₄⁻ + 8H⁺ + 5e → Mn²⁺ + 4H₂O.
- To obtain the net redox reaction, we multiply the oxidation reaction by 5 and the reduction reaction by 5 to equalize the no. of electrons in the two-half reactions.
<em>So, the net redox reaction will be:</em>
<em>3MnO₄⁻ + 24H⁺ + 5Au → 5Au³⁺ + 3Mn²⁺ + 12H₂O.</em>
<em></em>
CH₃-CH=CH₂ propene
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The answer:
according to Boyle's law concerning Pressure (P), Volume (V), Temperature (T) and number of mole (n) , we have the famous formula:
PiVi = Pf Vf,
Pi=1.9kPa
Vi= 4L
Vf = 12L
T=25
n=3
Pf = ?
let's find the value of Pf
from the equation
PiVi = Pf Vf we can have Pf= PiVi / Vf
Pf = 1.9*4 / 12 = 0.63
so the answer is <span>B. 0.63 kPa</span>
I’m pretty sure the answer is a as you go further down you will be heading towards the core meaning the temperature and will increase and I’m sure that will apply to pressure and density as well