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3 years ago

Is a electron found in a subtonic particles in a atomic nucleus

Chemistry

1 answer:

Ksju [112]3 years ago

3 0

An electron is found whizzing around the nucleus, so in subatomic particles.

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WARRIOR [948]

The snake,raccoon, and preying mantis

4 0

3 years ago

Jimmy mixes 2 chemicals in the lab. The chemicals change color and they get hot. The rise in temperature

gladu [14]

Answer:

A chemical reaction.

Explanation:

A change in temperature is evidence of a chemical reaction.

Also: They are chemicals...

3 0

3 years ago

The reaction C 4 H 8 ( g ) ⟶ 2 C 2 H 4 ( g ) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ / mol. 262 kJ/mol. At 600.0 K,

ludmilkaskok [199]

Answer: $4.3\times 10^{-13}s^{-1}$

Explanation:

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $775.0$ = $?$

$Ea$ = activation energy for the reaction = 262 kJ/mol = 262000J/mol

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $775.0K$

Now put all the given values in this formula, we get

$\log (\frac{6.1\times 10^{-8}}{K_2})=\frac{262000}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{775.0K}]$

$\log (\frac{6.1\times 10^{-8}s^}{K_2})=5.150$

$(\frac{6.1\times 10^{-8}}{K_2})=141253.8$

Therefore, the value of the rate constant at 775.0 K is $4.3\times 10^{-13}s^{-1}$

5 0

3 years ago

A carbon atom with 6 protons, 6 electrons, and 6 neutrons would have a mass number of

Nata [24]

12, electrons dont have mass. only protons and neutrons do

7 0

3 years ago

what is the total ionic and net ionic equation for for the reaction between between mercury (II) nitrate and iron (III) chloride

MArishka [77]

Answer:

Hg+2 + 2Cl- -> HgCl2

HOPE THIS HELPS HAVE A GREAT DAY/NIGHT!!~

Explanation:

7 0

2 years ago