1, 2, 3, or 4? i need this ASAP!! will give brainliest and a thanks to fast answers

There are 4 portable classrooms at Glynn High School. Four teachers will be assigned to the rooms. In how many ways can these as

Crank

Answer:

24

Step-by-step explanation:

In the first classroom, there are 4 possibilities of teachers to be assigned.

In the second classroom, 1 teacher has already been assigned, so there are 3 possibilities.

In the third classroom, 2 teachers have already been assigned, so there are only 2 possibilities.

Finally, there is only 1 possible teacher for the fourth classroom, since 3 teachers have already been assigned to other classrooms.

We can find the total number of possibilities using the product rule.

N = 4 × 3 × 2 × 1 = 24

7 0

2 years ago

Hello

Dafna11 [192]

Answer:

X=5

Exlanation

8 0

3 years ago

How do you expand expand (6 x)6.?

melamori03 [73]

The bracetes means ×
6×6=36 and there is more x
(6x)6=36x

8 0

3 years ago

Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.

lina2011 [118]

Tim has completed greater amount of work and overall they have completed 142/143 of the project work

Step-by-step explanation:

Given

Work completed by Jaime = j = 5/11

Work completed by Tim = t = 7/13

a. Who has completed the greater amount of work?

In order to see that we have to convert the fractions in decimal

So,

j = 5/11 = 0.45

t = 7/13 = 0.53

As we can see that the decimal for Tim's work space is large, Tim has completed greater amount of work

b. How much of the project have they completed together? Show your work.

We have to find the total work done by them

$Total\ work = j + t\\= \frac{5}{11} + \frac{7}{13}\\=\frac{65+77}{143}\\=\frac{142}{143}$

Hence,

Tim has completed greater amount of work and overall they have completed 142/143 of the project work

Keywords: Fractions, LCM

Learn more about fractions at:

#LearnwithBrainly

4 0

2 years ago

In a shipment of 2,000 beach balls 150 are defective the manufacturer generates a random sample to simulate 20 beach balls to in

Flauer [41]

The concluding part of the question as obtained from the textbook;

The number on the 20 beach balls that come up in the simulated sample:

42, 1701, 638, 397, 113, 1243, 912, 380, 769, 1312, 76, 547, 721, 56, 4, 1411, 1766, 677, 201, 1840

A) Based on this sample, how many

defective beach balls might the

manufacturer expect in the next

shipment?

B) What is the difference between the

number of defective beach balls in the

actual shipment and the number

predicted in the next shipment?

Answer:

A) 500 defective beach balls.

B) Difference between the

number of defective beach balls in the

actual shipment and the number

predicted in the next shipment = 350

Step-by-step explanation:

The beach balls are labelled 1 to 2000 with the 150 defective ones labelled 1 to 150.

Then a random sample of 20 beach balls is picked, and the numbers are presented as

42, 1701, 638, 397, 113, 1243, 912, 380, 769, 1312, 76, 547, 721, 56, 4, 1411, 1766, 677, 201, 1840

Note that only the defective beach balls have numbers 1 to 150.

A) The number of beach balls with numbers from 1 to 150 in the sample is 5 (numbers 42, 113, 76, 56, 4). This is the number of defective beach balls in the sample.

Probability of getting a defective ball in the next shipment = (5/20) = 0.25

If every shipment contains 2000 beach balls, then there will be (0.25 × 2000) defective beach balls in the next sample; 500 defective beach balls.

B) Number of defective beach balls in actual shipmemt = 150

Number of predicted defective beach balls in the next shipment = 500

difference = 500 - 150 = 350.

Hope this Helps!!!

8 0

3 years ago