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tresset_1 [31]
2 years ago
5

1, 2, 3, or 4? i need this ASAP!! will give brainliest and a thanks to fast answers

Mathematics
1 answer:
Ne4ueva [31]2 years ago
3 0

Answer:

Step-by-step explanation:

-10 since +5-15 =-10 so 2

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Using the slot method and multiple cases, calculate the probability that you would roll 3 sixes.
kotegsom [21]

Answer:

P = 1/216

the probability that you would roll 3 sixes is 1/216

Step-by-step explanation:

For a given dice, there are six possibilities.

We have;

1,2,3,4,5,6

The probability of rolling a six(6) is;

P(6) = 1/6

Then, the probability of rolling 3 sixes is a multiple of the P(6), given as;

P = P(6) × P(6) × P(6)

P = 1/6 × 1/6 × 1/6

P = 1/216

the probability that you would roll 3 sixes is 1/216

4 0
3 years ago
Limit (sin4x-4sinx)/x^3 when x close to zero
BartSMP [9]

\Large \boxed{\sf \bf \ \ \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}=-10 \ \  }

Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

sin(x) \sim  \left(x-\dfrac{x^3}{3!}\right)\\\\\text{So, in the neighbourhood of 0}\\\\\begin{aligned}(sin(4x)-4sin(x)) &\sim \left( 4x-\dfrac{(4x)^3}{3!}-4x+\dfrac{4x^3}{3!}\right)\\\\&\sim \left(\dfrac{x^3*4*(1-4^2)}{3*2}\right)\\\\&\sim \left(\dfrac{x^3*2*(-15)}{3}\right)\\\\&\sim \left(x^3*2*(-5)\right)\\\\&\sim \left(x^3*(-10)\right)\\\end{aligned}

Then,

\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10

Thank you

4 0
3 years ago
Read 2 more answers
Which of these is a finite population?
Inessa05 [86]
The best answer to go with is b
5 0
3 years ago
GIVING BRAINIEST!!!!!
dexar [7]

Answer:

Clearly, the probability of drawing a heart out of the deck is 13/52, or 1/4. The probability of drawing an even number as card #2 (∈{2,4,6,8,10}) for any suit is 20/51, except when the first card drawn is an even heart, then the probability of the second draw is 19/51.

5 0
3 years ago
Need helppppp asappppp
Temka [501]

it´s a polygon. letter c (decagon) should be right

hope it helps :)

8 0
2 years ago
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