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3 years ago

What is the fraction for 1261.4523

Mathematics

2 answers:

pickupchik [31]3 years ago

7 0

The answer might be this so try 12614523/10000

ioda3 years ago

4 0

I got 12614523/10000

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3(3y-4)=51 solve for y

Luba_88 [7]

Answer:

y = 7

Step-by-step explanation:

3 × (3y - 4) = 51 multiply 3 with inside the parenthesis

9y - 12 = 51 add like terms

9y = 51 + 12

9y = 63

y = 7

4 0

3 years ago

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Customers of a phone company can choose between two service plans for long distance calls. The first plan has a $28 monthly fee

aniked [119]

Answer:

POINTS

Step-by-step explanation:

7 0

1 year ago

What would be the equation for #23???

Rufina [12.5K]

Hi there!

Let r be the number of matches that Rebecca's team won.

We know that Katheryn's team won 9 more matches than Rebecca's team, and we know that Katheryn's team won 52 matches.

Using this given information, we can create the following equation.

$r+9=52$

If you wish to solve this, we can subtract both sides by 9 to get the following value for r.

$r=43$

Have an awesome day! :)

~collinjun0827, Junior Moderator

8 0

3 years ago

Read 2 more answers

the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr

Naily [24]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}$

$\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k$

$\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}$

5 0

3 years ago

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Write an equation that expresses the following relationship. w varies directly with u and inversely with d In your equation, use

Elena L [17]

Step-by-step explanation:

solution.

if variable d increases then w reduces

w=k.u ×1/d

=ku/d

therefore w=k.u/d

5 0

3 years ago