Answer:
Step-by-step explanation:
2/3 = 0.6 repeating
3/7 = 0.42857
Answer:
Let S = price of sweater
Let P = price of pants
S + P = 89.47 because that was the total spent
S = P - 8.53 because the sweater is 8.53 less than pants
Substitute P-8.53 in place of S in the
1st equation and solve for P
P - 8.53 + P = 89.47
2P - 8.53 = 89.47 add 8.53 to both sides
2P = 89.47 + 8.53
2P = 98.00 divide both sides by 2
P = 98.00/2
P = $49.00
S = P - 8.53
S = 49.00-8.53
S = $40.47
A sweater costs $40.47 and the pants cost $49.00
Answer:
Option C is correct.
Step-by-step explanation:
y = x^2-x-3 eq(1)
y = -3x + 5 eq(2)
We can solve by substituting the value of y in eq(2) in the eq(1)
-3x+5 = x^2-x-3
x^2-x+3x-3-5=0
x^2+2x-8=0
Now factorizing the above equation
x^2+4x-2x-8=0
x(x+4)-2(x+4)=0
(x-2)(x+4)=0
(x-2)=0 and (x+4)=0
x=2 and x=-4
Now finding the value of y by placing value of x in the above eq(2)
put x =2
y = -3x + 5
y = -3(2) + 5
y = -6+5
y = -1
Now, put x = -4
y = -3x + 5
y = -3(-4) + 5
y = 12+5
y =17
so, when x=2, y =-1 and x=-4 y=17
(2,-1) and (-4,17) is the solution.
So, Option C is correct.
Answer:
t=3.5 seconds
Step-by-step explanation:
Given
h(t) = −16t^2 + 111t + 0
h'(t)= -32t + 111
Maximum height occurs when h(t) = 0 and the ball begins to fall
h(t)= -32t + 111=0
-32t + 111=0
-32t=-111
Divide both sides by -32
t=3.46872
Approximately, t=3.5 seconds
Recall,
Maximum height occurs when h(t) = 0
h(t)= -32t + 111=0
= -32(3.46872)+111
= -110.99904+111
= 0.00096 ft
