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Kobotan [32]
3 years ago
13

If r= 37 find the values of p, q, s

Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

ckfgfuf go he z v g b I g to

Step-by-step explanation:

c I'm x go bc to ggzh it ti

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Which three measurements could be the lengths of the sides of a triangle?
laila [671]

Answer:

i'm guessing b or a sorry if i'm wrong TwT

Step-by-step explanation:

sorry

3 0
3 years ago
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The area is no more than 40 square feet. Write and solve an inequality that represents the value of x
Anna35 [415]

Answer:

well its a triangle so

40 divide by 20 is 2

but you have to mutiply that 2 by 2

Step-by-step explanation:

4

3 0
2 years ago
Find the unknown angle measure.
Fofino [41]

Answer:

58 degrees

Step-by-step explanation:

add the 2 shown, 74+48, to get 122 all triangles add up to 180 so subtract 122 from 180 and you get 58

7 0
3 years ago
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Please solve with explanation (high points)
Hunter-Best [27]

Step-by-step explanation:

so, we have a large triangle made of the 2 cables as legs and the ground distance AB as baseline.

the tower is the height to the baseline of that large triangle.

let's call the top of the tower T.

and remember, the sum of all angles in a triangle is always 180°.

we know the angle A = 62°, and angle B = 72°.

assuming that AB is a truly horizontal line that means that the 2 legs (cables) have different lengths, the triangle is not isoceles, and the tower is not in the middle of the baseline.

so, the height (tower) splits the baseline into 2 parts. let's call them p and q.

p + q = 12 m

p = 12 - q

let's simply define that p is the part of the baseline on the A side, and q is the part of the baseline on the B side.

we have now 2 small right-angled triangles the large height (tower) splits the large triangle into.

one has the sides

AT, height (tower), p

angle A = 62°

angle T = 180 - 90 - 62 = 28°

the other has the sides

BT, height (tower), q

angle B = 72°

angle T = 180 - 90 - 72 = 18°

now remember the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the sides and the associated angles being opposite.

p/sin(28) = height/sin(62)

q/sin(18) = height/sin(72)

we know from above that

p = 12 - q

so,

(12 - q)/sin(28) = height/sin(62)

height = (12 - q)×sin(62)/sin(28)

q/sin(18) = height/sin(72)

height = q×sin(72)/sin(18)

and therefore, as height = height we get

(12 - q)×sin(62)/sin(28) = q×sin(72)/sin(18)

(12 - q)×sin(62)×sin(18) = q×sin(72)×sin(28)

12×sin(62)×sin(18) - q×sin(62)×sin(18) =

= q×sin(72)×sin(28)

12×sin(62)×sin(18) = q×sin(72)×sin(28) + q×sin(62)×sin(18) =

= q×(sin(72)×sin(28) + sin(62)×sin(18))

q = 12×sin(62)×sin(18) / (sin(72)×sin(28) + sin(62)×sin(18))

q = 4.551603755... m

p = 12 - q = 7.448396245... m

height = q×sin(72)/sin(18) = 14.00839594... m ≈ 14 m

the cell tower is about 14 m tall.

7 0
1 year ago
The formula P=a+b+c gives perimeter P of triangle side lengths a,b,and c how much greater is perimeter when triangle measures 33
seropon [69]

Answer:

41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

First we have to calculate the perimeter of 1st triangle.

Given:

a = 33 yards

b = 56 yards

c = 65 yards

Now we have to calculate the perimeter of 2nd triangle.

Given:

a = 26 yards

b = 49  yards

c = 38 yards

Now we have to calculate which triangle has greater perimeter and how much greater.

Therefore, 41 yards greater is the perimeter of 1st triangular field than the perimeter of 2nd triangular field.

Step-by-step explanation:

(154-113)

41 yards bigger

3 0
2 years ago
Read 2 more answers
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