All categories

2 years ago

I NEED HELP ON THIS CONSTRUCTED RESPONSE! :(

Mathematics

1 answer:

Simora [160]2 years ago

7 0

Answer:

Step-by-step explanation:

(9/2)(8 - x) + 36 = 102 - (5/2)(3x + 24)

Multiply both sides by 2.

9(8 - x) + 2 * 36 = 2 * 102 - 5(3x + 24)

Distribute on both sides.

72 - 9x + 72 = 204 - 15x - 120

Combine like terms on each side.

144 - 9x = 84 - 15x

Subtract 144 from both sides. Add 15x to both sides.

6x = -60

Divide both sides by 6.

x = -10

You might be interested in

Joseph made a model rocket by attaching a cone

Lerok [7]

Answer:

Area = 270π inches squared. Volume = 550π inches cubed

Step-by-step explanation:

Surface Area:

Cylinder Area=2πrh+2πr^2= 180π+50π=230π inches squared.

Cone Area = πr(r+√(h^2+r^2)) = 5π(18) = 90π inches squared.

Total Area = 230π+90π = 320π inches squared.

Total Area - base = 320π-50π = 270π inches squared.

Volume:

Cylinder volume = πr^2h = 450π inches cubed

Cone volume = πr^2(h/3) = 100π inches cubed

Total Volume = 550π inches cubed

4 0

2 years ago

Dax is buying hot chocolate for 5 people in his office (including himself). He pays for the 5 drinks and leaves a $2.00 tip.

ANEK [815]

Answer: Each cup of hot chocolate is $3.25

Step-by-step explanation:

3 0

2 years ago

Help for Geometry #6 and 7

Arturiano [62]

Find the area of the rectangle and the 1/2 circle, then subtract the half circle's area from the rectangle's.
Area of the rectangle is 30in.
Area of the 1/2 circle is 19.625.
Subtract
30-19.625
10.375
(Round it to 10.4 in this case)

8 0

2 years ago

A committee must be formed with 5 teachers and 4 students. If there are 6 teachers to choose from, and 15 students, how many dif

ZanzabumX [31]

Answer:

8190 ways

Step-by-step explanation:

Given

$Teachers = 6$

$Students = 15$

Selection

$Students = 4$

$Teachers = 5$

Required

Number of ways of selection

4 students can be selected from 15 students in:

$Students= ^{15}C_4$

Similarly.

5 teachers can be selected from 6 teachers in:

$Teachers= ^{6}C_5$

So, the required number of selection is:

$Selection = ^{15}C_4 * ^6C_5$

Apply combination formula:

$Selection = \frac{15!}{(15-4)!4!} * \frac{6!}{(6-5)!5!}$

$Selection = \frac{15!}{11!4!} * \frac{6!}{1!5!}$

$Selection = \frac{15*14*13*12*11!}{11!*4*3*2*1} * \frac{6*5!}{1*5!}$

$Selection = \frac{15*14*13*12}{4*3*2*1} * \frac{6}{1}$

$Selection = \frac{32760}{24} * 6$

$Selection = 1365 * 6$

$Selection = 8190$

8 0

2 years ago

How do I solve this? Thank you!

Marat540 [252]

Probably A but not sure

3 0

2 years ago