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kupik [55]
3 years ago
10

In a high school with 5,000 students, the number of text messages sent by each student during a particular month was recorded. T

he mean number of text messages sent during the month was 55 per student.
If the data was normally distributed, and if the standard deviation of the data was 4 text messages, which of these is the BEST estimate for the number of students who sent fewer than 51 text messages during the month?
Mathematics
2 answers:
koban [17]3 years ago
8 0
Hi
Question : 
<span>If the data was normally distributed, and if the standard deviation of the data was 4 text messages, which of these is the BEST estimate for the number of students who sent fewer than 51 text messages during the month?

  4
x 51
----------
204

Answer : 
204

I hope it helps and if it is correct please press brainlest 
~Rie</span>
algol [13]3 years ago
7 0

Answer:

The answer is 800

Step-by-step explanation:

Since the data is normally distributed, 68% of the data is within 1 standard deviation of the mean. This means that 68% of the students sent between 55 – 4, or 51, and 55 + 4, or 59 text messages during the month. For this reason, 32% of the students did not send between 51 and 59 text messages during the month. Half of the 32% sent fewer than 51 text messages, and the other half of the 32% sent more than 59 text messages. Therefore, since 16% of the 5,000 students sent fewer than 51 text messages, a valid expectation for the number of students who sent fewer than 51 text messages during the month is 800.

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koban [17]

Step-by-step explanation:

360 - 126 =234

234 ÷3x

x = 78

8 0
2 years ago
Help help please will give brainliest PLEASE DON'T ANSWER IF YOU DON'T KNOW THE ANSWER​
sergey [27]

Answer:

0 is the answer. I think.

5 0
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kaheart [24]

Answer:

375 fishes

Step-by-step explanation:

12000 divided by 2 is 6000 1st year

6000 divided by 2 is 3000 2nd year

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3 years ago
12x⁴y²divided by 3x³y to the 5 th power....Please help me out....
ki77a [65]
To divide the expression we proceed as follows:
12x⁴y²÷3x³y⁵
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5 0
3 years ago
According to a National Health Survey, American men’s heights are normally distributed with a mean given by μ=69.7 inches and a
Novay_Z [31]

Answer: 0.206

Step-by-step explanation:

Given that :

Height of American men is normally distributed :

Mean height (μ) = 69.7 inch

Standard deviation (σ) = 2.8 inch

Probability that height of a randomly selected man is more than 72 inches

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6 0
3 years ago
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