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3 years ago

Which graph represents the function below?

Mathematics

2 answers:

Vinvika [58]3 years ago

6 0

It's the first image. (The one that looks like V)

Andreyy893 years ago

3 0

Answer:

<h2>First graph.</h2>

Step-by-step explanation:

Notice that in the piecewise functions, both parts have opposite slopes 2 and -2, that means the lines are perpendicular.

Also, the negative slope line must intercept y-axis at (0,3).

The positive slope line must intercept y-axis at (0,-1).

Additionally, the function indicates that to every x-value less than 1, the function is a decreasing line. And, for every x-value greater or equal than 1, the function is an increasing line.

Therefore, the first graph, represents the given piecewise function, because it has all the characteristics indicated by the function.

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Keith earns $37.00 in 4 hours. How much would he earn in 11 hours?

Leona [35]

Answer:

Step-by-step explanation:

37/4= 9.25

9.25*11 =101.75

7 0

3 years ago

Read 2 more answers

What is 925/1000 in simplest form

mojhsa [17]

37/40 37 divide it by 25 and it comes out 37 and if you divide 25 into 1000 in comes out to be 40

8 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$