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Pachacha [2.7K]
3 years ago
5

Over which interval are the exponential and linear function approximately the same? from 0.25 to 0.5 from 0.5 to 0.75 from 0.75

to 1.0 from 1.25 to 1.5
Mathematics
2 answers:
rewona [7]3 years ago
8 0

Answer:

the answer is C 0.75 to 1.0

ryzh [129]3 years ago
3 0

Answer:

Answer is 0.25 to 0.5

Step-by-step explanation:

Let the linear function be y=x

and exponential function be y=e^x

x          0.25   0.5    0.75    1.0     1.25    1.5

y          0.25   0.5    0.75    1.0     1.25    1.5

Diff             0.25  0.25  0.25   0.25  0.25

e^x      1.29   1.65    2.12     2.72  3.49    4.48

Diff            0.36  0.47     0.60   0.77    0.99

Hence 0.36 to be nearer to 0.25, than other intervals

So answer is 0.25 to 0.5

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3 years ago
Does the series converge or diverge? If it converges, what is the sum? Show your work. ∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Given the series,

∑ ∞ n = 1 − 4 ( − 1 / 2 ) n − 1

I think the series is summation from n = 1 to ∞ of -4(-1/2)^(n-1)

So,

∑ − 4 ( − ½ )^(n − 1). From n = 1 to ∞

There are different types of test to show if a series converges or diverges

So, using Ratio test

Lim n → ∞ (a_n+1 / a_n)

Lim n → ∞ (-4(-1/ 2)^(n+1-1) / -4(-1/2)^(n-1))

Lim n → ∞ ((-4(-1/2)^(n) / -4(-1/2)^(n-1))

Lim n → ∞ (-1/2)ⁿ / (-1/2)^(n-1)

Lim n→ ∞ (-1/2)^(n-n+1)

Lim n→ ∞ (-1/2)^1 = -1/2

Since the limit is less than 0, then, the series converge...

Sum to infinity

Using geometric progression formula

S∞ = a / 1 - r

Where

a is first term

r is common ratio

So, first term is

a_1 = -4(-½)^1-1 = -4(-½)^0 = -4 × 1

a_1 = -4

Common ratio r = a_2 / a_1

a_2 = 4(-½)^2-1 = -4(-½)^1 = -4 × -½ = 2

a_2 = 2

Then,

r = a_2 / a_1 = 2 / -4 = -½

S∞ = -4 / 1--½

S∞ = -4 / 1 + ½

S∞ = -4 / 3/2 = -4 × 2 / 3

S∞ = -8 / 3 = -2⅔

The sum to infinity is -2.67 or -2⅔

Check attachment for better understanding

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The given ratio of the sides of the triangles is 4:10:7. Let the sides be 4x, 10x and 7x .

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