Answer:
x = -11
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
Terms/Coefficients
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify.</em>
-3(x + 2) = 16 - x
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute -3: -3x - 6 = 16 - x
- [Addition Property of Equality] Add <em>x</em> on both sides: -2x - 6 = 16
- [Addition Property of Equality] Add 6 on both sides: -2x = 22
- [Division Property of Equality] Divide -2 on both sides: x = -11
Pretty sure it’s 42.5 cm.
The right answer for the question that is being asked and shown above is that: "d. The value of a number substituted for x is greater than 6.; b. The solution set is {6, 7, 8, …} for x ∈ N."<span> These are the statements and number lines that can represent the inequality. </span>
Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find
