Step-by-step explanation:
so we know X= Numbers of Large boxes and Y= Numbers of Small boxes
And we know the large boxes weigh <em>7</em><em>5</em><em><u> </u></em><em><u>pounds</u></em> and the small boxes weigh <em>4</em><em>0</em><em> </em><em><u>pounds</u></em>
So I would have to say the the same except you have to flip the inequality sign like this:
75x + 40y

200
And if that doesnt somehow work and the question is wording it wrong then
My guess for why its wrong us because its not in slope intercept form Although you still can solve for either varible ( x or y) using standard form also.
So to get from standard form to Slope intercept form (y=mx+b) these are the steps:
Ax+by=C
75x + 40y ≤ 200
Turn it into a linear equation.
75x+ 40y =200
In order to go from one form to another, all you have to do is change the order of the given numbers. First you want to move the Ax to the opposite side of the equation, by either adding or subtracting it. At this point your equation will be set up By = -Ax + C. Then you want to divide the B from the By and the rest of the equation. Therefore you will have y = - Ax/B + C/B. This is the same thing as the slope-intercept form, just a few of the letters are different.
40y=-75x+200 first subtract 75x
y=−1.875×+5 then dived every varible (everything) by 40. and you have your Linear eqaution.
And your second question would be <em><u>A</u></em><em><u>.</u></em><em><u> </u></em><em><u>>The number of boxes must be a whole number.</u></em><em><u> </u></em>
Because you cannot split boxes in half or in any quarter in a real life scenario.
Answer:
add 8 to 2 and then multiply the 8 with 12.
Step-by-step explanation:
8n
Hope it helps, good luck
Answer:
Ah yes rsm.
Anyways, AB is parallel to DE so 72= angle BDE. So BDE+2x+2x=180
72+4x=180
108=4x
x=27
Answer:
a) No
b) 42%
c) 8%
d) X 0 1 2
P(X) 42% 50% 8%
e) 0.62
Step-by-step explanation:
a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.
b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6
P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7
P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%
c) P(win first game) = 0.4
P(win second game) = 0.2
P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%
d) X 0 1 2
P(X) 42% 50% 8%
P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%
P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%
e) The expected value 
f) Variance 
Standard deviation 