Which number is irrational

16. What is the area of a triangle that has a base of 8 inches and a height of 3 inches?

Luden [163]

<h2>Answer:</h2>

A=12in²

Step-by-step explanation:

b Base 8in

hb Height 3in

A=hbb

2=3·8

2=12in²

7 0

2 years ago

Tries remaining: 3Points out of 1.00Not flaggedFlag question

Dmitrij [34]

$\rm\underline\bold{Answer \purple{\huge{\checkmark}}}$

C.

A = A0e^-0.000103k

7 0

3 years ago

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Linda is running the concession stand at a basketball game. She sells hot dogs fir $2 and drinks for $1.50. She made a total of

Ede4ka [16]

Answer:

53 hotdogs

Step-by-step explanation:

1.50 x 64 = 96

202 - 96 = 106

106 ÷ 2 = 53

6 0

3 years ago

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Please help 1. Find the rectangular coordinates of (7, 150°).

cupoosta [38]

Answer:

Step-by-step explanation:

$x=r cos \theta=7 cos150=7cos(180-30)=-7cos ~30=-\frac{7\sqrt{3} }{2} \\y=r~sin~\theta=7~sin ~150=7~sin~(180-30)=7~sin~30=\frac{7}{2} \\so ~coordinates ~are~(-\frac{7\sqrt{3}}{2} ,\frac{7}{2} )\\C$

8 0

3 years ago

PLEASE HELP.

OverLord2011 [107]

Answer:

Explicit formula for

1) $a_n=17-3(n-1)$

2) $a_n=(\frac{1}{2} )^{n-1}\cdot 20$

Step-by-step explanation:

W have to find the first few terms of the given sequence and then find an explicit equation

Explicit formula = f(n) + d(n-1) , where,

f(n) is first term,

d is common difference,

n-1 is one term less than the term number.

1)

Given : $a_1=17\\\\a_{n+1}=a_n-3$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

2)

Given : $a_1=20\\\\a_{n+1}=\frac{1}{2} \cdot a_n$

$\text{We put n =1, we get,}\\\\a_2=a_1-3=17-3=11=17-3(2-1)\\\\\\\text{We put n =2, we get,}\\\\\\a_3=a_2-3=11-3=8=17-3-3=17-3\cdot 2=17-3(3-1)\\\\\text{We put n =3, we get,}\\\\\\a_4=a_3-3=8-3=5=17-3-3-3=17-3\cdot 3=17-3(4-1)\\$

Thus, we obtained an explicit formula,

$a_n=17-3(n-1)$

$\text{We put n =1, we get,}\\\\\\a_2=\frac{1}{2} \cdot a_1=\frac{1}{2} \cdot 20=10=(\frac{1}{2} )^{2-1}\cdot 20\\\\\\\text{We put n =3, we get,}\\\\\\a_4=\frac{1}{2} \cdot a_3=\frac{1}{2} \cdot 5=\frac{5}{2}=(\frac{1}{2} )^{4-1}\cdot 20\\\\\\$

Thus, we obtained an explicit formula,

$a_n=(\frac{1}{2} )^{n-1}\cdot 20$

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2 years ago

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