Answer:
6
Step-by-step explanation:
they are the same length as the shape it got reflected off of.
Answer:
25.6 units
Step-by-step explanation:
From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).
First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

where
are the coordinates of the first point
are the coordinates of the second point
- For AB:
![d=\sqrt{[1-(-5)]^{2}+(4-4)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B1-%28-5%29%5D%5E%7B2%7D%2B%284-4%29%5E2%7D)



- For BC:





- For AC:
![d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%5B3-%28-5%29%5D%5E%7B2%7D%20%2B%28-4-4%29%5E%7B2%7D%7D)





Next, now that we have our lengths, we can add them to find the perimeter of our triangle:




We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.
45.5 is your answer, you will have to multiple the height times the base ( 5 x 9.1 )