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Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x )² = 4 x
m²
Length 'L' = 5m
current '' = 2 A
density of free electrons 'n'= 8.5 x /m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x
|)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
Answer:
Explanation:
As we know the , equation of time period for simple pendulum ,
T = 2*pi*
hence putting values we get ,
the solution is in picture ,
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