All categories

3 years ago

Honey bees beat their wings, making a buzzing sound at a frequency of 2.3 × 102 hertz. What is the period of a bee's wing beat?

Physics

1 answer:

Phantasy [73]3 years ago

8 0

1/2.3 = 0.4347

Hence the only answer possible is A = 4.3e-3 and the frequency is 2.3e3 Hz

You might be interested in

What is the definition of a volt in science?

OverLord2011 [107]

One volt is defined as the difference in electric potential between two points of a conducting wire when an electric current of one ampere dissipates one watt of power between those points.

4 0

3 years ago

The midpoint M of a guitar string is pulled a distance d = 1.7 mm from equilibrium and released. Point M is observed to undergo

nlexa [21]

Answer:

ω = 380π rad/s

Explanation:

The formula for the angular frequency is the oscillation frequency f (hertz) multiplied by 2π

ω = 2πf

then

ω = 2π(190)

ω = 380π rad/s

8 0

3 years ago

A package is dropped from an air balloon two times. In the first trial the distance between the balloon and the surface is Hand

enyata [817]

Answer:

The final speed of the second package is twice as much as the final speed of the first package.

Explanation:

Free Fall Motion

If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:

$v=gt$

And the distance traveled downwards is:

$\displaystyle y=\frac{gt^2}{2}$

If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:

$\displaystyle t=\sqrt{\frac{2y}{g}}$

Replacing into the first equation:

$\displaystyle v=g\sqrt{\frac{2y}{g}}$

Rationalizing:

$\displaystyle v=\sqrt{2gy}$

Let's call v1 the final speed of the package dropped from a height H. Thus:

$\displaystyle v_1=\sqrt{2gH}$

Let v2 be the final speed of the package dropped from a height 4H. Thus:

$\displaystyle v_2=\sqrt{2g(4H)}$

Taking out the square root of 4:

$\displaystyle v_2=2\sqrt{2gH}$

Dividing v2/v1 we can compare the final speeds:

$\displaystyle v_2/v_1=\frac{2\sqrt{2gH}}{\sqrt{2gH}}$

Simplifying:

$\displaystyle v_2/v_1=2$

The final speed of the second package is twice as much as the final speed of the first package.

5 0

3 years ago

A traffic accident detective measures the skid marks left by a car, 825kg. He determines that the distance between the point tha

deff fn [24]

Doing a force balance on the car:
ma = Fr
ma = μmg
a = μg
a = 0.3(9.81)
a = 29.43 m/s2

Using the formula:
2ax = v2
2(29.43)(34) = v2
v = 44.74 m/s = 161.05 km/h

The car was going 44.74 m/s or 161.05 kph when the brakes were applied.

7 0

3 years ago

What is the acceleration of a the BMW i8 Roadster that goes from 0 to 60 mph in 3.8 seconds? A) in mi/h/s and b) in m/s^2

Nataly_w [17]

Answer:

a) 15.78 mi/h/s

b) 7.105 m/s^2

Explanation:

a) It is given that speed changes from 0 to 60 miles per hour (mph)

Acceleration is equal to change in speed divided by time

$a = \frac{60-0}{3.8} \\a = 15.78$ mi/h/s

1 mile/h = 0.45 m/s

Acceleration in m/s^2

$15.78 * 0.45 = 7.105$ m/s^2

8 0

2 years ago