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shtirl [24]
3 years ago
11

2x - y = 3 y = -x What’s the value of x?

Mathematics
2 answers:
pashok25 [27]3 years ago
6 0

Answer:

X = 1 which means Y = -1

Step-by-step explanation:

2x - y = 3                    

y = -x                              

Sub for y

2x + x = 3

Add the x's

3x = 3

Divided by 3

x = 1

zlopas [31]3 years ago
3 0

Answer:

These are simultaneous equations.They have to be solved like this:

2x-y=3 -y=3-2x 2x-3= -x

y= -x y= -(3-2x) 3x= 3

y=2x-3 x=1

Step-by-step explanation:

The value of x equals to 1

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This a circle centered at the point (-6,-5), and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point (x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1)  R^2 = 9\,\,\,then\,\,\,R=3  since the radius must be a positive number and (R=-3) is not a viable answer.

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3) y_0=-5    for ( y-y_0) to equal   (y+5)

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Read 2 more answers
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
4 years ago
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