Given expression is
![\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E%7B11%7Dy%5E8%7D%7B81x%5E7y%5E6%7D%7D)
Radical is fourth root
first we simplify the terms inside the radical


So the expression becomes
![\sqrt[4]{\frac{16x^4y^2}{81}}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%5Cfrac%7B16x%5E4y%5E2%7D%7B81%7D%7D)
Now we take fourth root
![\sqrt[4]{16} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%202)
![\sqrt[4]{81} = 3](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81%7D%20%3D%203)
![\sqrt[4]{x^4} = x](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E4%7D%20%3D%20x)
We cannot simplify fourth root (y^2)
After simplification , expression becomes
![\frac{2x\sqrt[4]{y^2}}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5Csqrt%5B4%5D%7By%5E2%7D%7D%7B3%7D)
Answer is option B
Let
A (1,6)------> location <span>brianna's house on a map
B </span>(5,3)------> location Jordan's house on a map
we know that
One possible path from brianna's house to jordan's house it's a straight line ( <span>the shortest distance)</span>
using a graph tool
see the attached figure
find the distance points AB
d=√[(y2-y1)²+(x2-x1)²]-----> d=√[(3-6)²+(5-1)²]----> d=√[3²+4²]
d=√25----> d=25 units
the distance from brianna's house to jordan's house is 25 units
Answer:
Step-by-step explanation:
40.2=3(x+2)
134=10x+20
134-20=10x+20-20
114=10x
11.4=x