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3 years ago

I am still lost.....

Mathematics

1 answer:

exis [7]3 years ago

4 0

-3(-15w+2)
You have to use the distributive property to simplify this expression.
-3 times -15w is 45w.
-3 times 2 is -6.

-3(-15w+2)
45w-6 is the answer

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If 7a - 11b = 0, what will be the value of a:b

Lilit [14]

Answer:

11:7

Step-by-step explanation:

Solution

Here

7a-11b=0

a:b=?

we know that

a=7

b=11

ans =11:7

Hence proved

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24.459 correctly rounded to the hundredths place?

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3 years ago

Given that the two lines are parallel, solve for x and find the measure of the labeled angle.

Aliun [14]

Answer:

x= 30

The angles measure 80 degrees

Step-by-step explanation:

The two angles are corresponding angles and, when the lines are parallel, corresponding angles are equal.

2x+20 = 3x-10

Subtract 2x from each side

2x+20-2x = 3x-10-2x

20 = x-10

Add 10 from each side

20+10=x-10+10

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5 0

2 years ago

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A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp

Shtirlitz [24]

Answer:

$98.90-1.984\frac{0.62}{\sqrt{103}}=96.98$

$98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82$

The 95% confidence interval would be given by (96.98;100.82)

Step-by-step explanation:

Information given

$\bar X=98.90$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=103-1=102$

Since the Confidence is 0.95 or 95%, the significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value for this case would be $t_{\alpha/2}=1.984$

And replacing we got:

$98.90-1.984\frac{0.62}{\sqrt{103}}=96.98$

$98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82$

The 95% confidence interval would be given by (96.98;100.82)

8 0

4 years ago