Answer
A Personal statement
Explanation
A personal statement essay is one that a person state his or her achievements and qualifications in a manner will convince the admission board members to accept the application to join the learning institution. It is similar to a college admission essay.
No Meeks or Gadies have hands and no legs.
The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
![SE = \frac{\sigma}{\sqrt n}](https://tex.z-dn.net/?f=SE%20%3D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%20n%7D)
The standard error of the Canadian sample is:
![SE_1 = \frac{2.9}{\sqrt{50}}](https://tex.z-dn.net/?f=SE_1%20%3D%20%5Cfrac%7B2.9%7D%7B%5Csqrt%7B50%7D%7D)
So, we have:
![SE_1 = 0.41](https://tex.z-dn.net/?f=SE_1%20%3D%200.41)
The standard error of the American sample is:
![SE_2 = \frac{1.3}{\sqrt{60}}](https://tex.z-dn.net/?f=SE_2%20%3D%20%5Cfrac%7B1.3%7D%7B%5Csqrt%7B60%7D%7D)
So, we have:
![SE_2 = 0.17](https://tex.z-dn.net/?f=SE_2%20%3D%200.17)
The standard error of the difference of sample means is then calculated as:
![SE= \sqrt{SE_1^2 + SE_2^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7BSE_1%5E2%20%2B%20SE_2%5E2%7D)
This gives
![SE= \sqrt{0.41^2 + 0.17^2}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.41%5E2%20%2B%200.17%5E2%7D)
![SE= \sqrt{0.197}](https://tex.z-dn.net/?f=SE%3D%20%5Csqrt%7B0.197%7D)
Take square roots
![SE= 0.444](https://tex.z-dn.net/?f=SE%3D%200.444)
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at:
brainly.com/question/6851971