Answer:
Q13. y = sin(2x – π/2); y = - 2cos2x
Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1
Step-by-step explanation:
Question 13
(A) Sine function
y = a sin[b(x - h)] + k
y = a sin(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Phase shift = π/2.
2h =π/2
h = π/4
The equation is
y = sin[2(x – π/4)} or
y = sin(2x – π/2)
B. Cosine function
y = a cos[b(x - h)] + k
y = a cos(bx - bh) + k; bh = phase shift
(1) Amp = 1; a = 1
(2) The graph is symmetrical about the x-axis. k = 0.
(3) Per = π. b = 2
(4) Reflected across x-axis, y ⟶ -y
The equation is y = - 2cos2x
Question 14
(A) Sine function
(1) Amp = 2; a = 2
(2) Shifted down 1; k = -1
(3) Per = π; b = 2
(4) Phase shift = 0; h = 0
The equation is y = 2sin2x -1
(B) Cosine function
a = 2, b = -1; b = 2
Phase shift = π/2; h = π/4
The equation is
y = -2cos[2(x – π/4)] – 1 or
y = -2cos(2x – π/2) - 1
1000+9 x 100 + 9 x 10 + 3 x 1 or 1000 + 900+ 90 + 3
(A)
Choice (B) is not the right answer because I
it's only 3rd order. But because f(x) goes to negative infinity when x goes to positive infinity means that the right answer is (A).
Answer:
The answer to your question is: 3x³ - x² - 4x - 2
Step-by-step explanation:
Data
3x⁴ + 2x³ - 5x² - 6x - 2
x + 1
Process
Synthetic division
3 2 -5 - 6 -2 -1
-3 1 4 2
3 -1 -4 -2 0
Result 3x³ - x² - 4x - 2
