How do i do these??? please help me

Mathematics

1 answer:

BARSIC [14]4 years ago

4 0

Do u have another picture I cant realy see it

You might be interested in

Evaluate the expression 82+5*7-12+36

vaieri [72.5K]

your answer would be 141

5*7=35

82+35=117

117-12=105

105+36=141

8 0

4 years ago

A certain number of friends are waiting in line to board a new roller coaster. they can board the ride in 5,040 different ways.

Paraphin [41]

There are seven (7) friends.

The first friend to board can be any one of the 7. For each of them ...
The 2nd one to board can be any one of the remaining 6. For each of them ...
The 3rd one to board can be any one of the remaining 5. For each of them ...
The 4th one to board can be any one of the remaining 4. For each of them ...
The 5th one to board can be any one of the remaining 3. For each of them ...
The 6th one to board can be either of the remaining 2. For each of them ...
The 7th one to board is the last 1 standing.

The number of different ways that this could play out is

(7 x 6 x 5 x 4 x 3 x 2 x 1) = <em>5,040</em>

6 0

3 years ago

Jessica bought 1/2 pound of roast beef and 5/6 pound of ham. Which pairs of fractions are equivalent to the amounts Jessica boug

Effectus [21]

Answer is
B aka D but simplified

5 0

3 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

4 years ago

Find the midpoint between two points on a coordinate plane whose coordinates are (5,7) and (-3,1)

hoa [83]

Step-by-step explanation:

Mid point formula ,

x = (x1+x2)/2 , y = (y1+y2)/2

x = 1 , y = 4

therefore ,midpoint is (x, y)= (1,4)

4 0

3 years ago

Read 2 more answers