Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
the picture is kinda blur but nvm
Step-by-step explanation:
3:b
4:b
5:a
6:b
Answer:
2÷(−2) = -1
Step-by-step explanation:
35% packed their lunch. 65/100 bought hot lunch. 100-65=35.
