Need help with this please. Given the following functions: f(u)=tan(u) and g(x)=x^9. Find:
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
We need to find the equation of the line perpendicular to the line 3x+2y=8 and passes through (-5,2).
The given line can be expressed as:
We can see the slope of this line is m1=-3/2.
The slopes of two perpendicular lines, say m1 and m2, meet the condition:
Solving for m2:
Now we know the slope of the new line, we use the slope-point form of the line:
Where m is the slope and (h,k) is the point. Using the provided point (-5,2):
-x+3y+3=0 <-- This puts the expression into an equation to make it solvable.
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
-1 <-- Use Division Property of Exponents to remove the 3 from y
y=-1 < This is the equation for the y-intercept
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!
3y+3=x <-- Use Addition Property of Exponents to move the (x) to the right
3y=x-3 <-- Use Subtraction Property of Exponents to move the (3) to the right
y=
y=
-x+3y+3=0 <-- Same as above, makes it so the expression is an equation to solve
-x+3=-3y <-- Use Subtraction Property of Exponents to move the 3y to the right
-x=-3y-3 <-- Use Subtraction Property of Exponents to move the 3 to the right
x=3y+3 <--Use Divison Property of Exponents to remove the -1 from x
x=3y+3 <-- This is the equation for the x-intercept
Hope this helped!