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larisa [96]
3 years ago
9

Determine the distance between -7 and 7.

Mathematics
1 answer:
umka21 [38]3 years ago
6 0
It is D) 14 Units because it takes seven units to get from -7 to zero and 7 units to get from 0 to 7. there fore 7+7=14.
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In ΔABC, the measure of ∠C=90°, the measure of ∠B=15°, and BC = 2.8 feet. Find the length of CA to the nearest tenth of a foot.
8090 [49]

Answer:0.8 feet

Step-by-step explanation:got it right

7 0
3 years ago
Ally's little sister wanted to help her make some oatmeal cookies. first ,she put 5/8 cup 0f oatmeal in the bowl. next,she added
Colt1911 [192]
15/8 cups or 1 and 7/8 of acup
8 0
4 years ago
Read 2 more answers
A special deck of cards has ten cards. Four are green, three are blue, and three are red. When a card is picked, its color of it
nata0808 [166]

Answer:

P(A) = 3/20

Step-by-step explanation:

P(A)=P(blue)P(head)=(3/10)(1/2)=3/20

as there are 10 cards in total, out of which 3 are blue so the probability to get the blue card is, P(blue) = 3/10. and the probability of getting a head when a coin is tossed is P(head) = 1/2.

So in total

P(A) = P(blue)*p(head) = (3/10)*(1/2) = 3/20 = 0.15

8 0
3 years ago
How do you do these problems?
Angelina_Jolie [31]

Answer:

18e⁶

⁵/₁₂₈

Step-by-step explanation:

Rₙ(x) = f⁽ⁿ⁺¹⁾(c) / (n+1)! (x − a)ⁿ⁺¹, and a < c < x.

f(x) = eˣ, a = 0, and n = 1.  Thus R₁ is:

R₁(x) = f"(z)/2! x²

R₁(x) = eᶻ/2 x²

|R₁| is a maximum when |f"(z)| is a maximum.  On the domain 0 < z < 6, that maximum is e⁶.  At x = 6, the upper bound of |R₁| is:

|R₁| = 18e⁶

This time, f(x) = 1 / √(1 + x) = (1 + x)^-½.  a = 0, and n = 2.

R₂(x) = f⁽³⁾(z)/3! x³

Find f⁽³⁾(x):

f'(x) = -½ (1 + x)^-³/₂

f"(x) = ¾ (1 + x)^-⁵/₂

f⁽³⁾(x) = -¹⁵/₈ (1 + x)^-⁷/₂

On the domain -½ < z < 0, |f⁽³⁾(z)| is a maximum at z = 0.

|f⁽³⁾(z)| = ¹⁵/₈

Therefore, at x = -½, the upper bound of R₂ is:

|R₂| = (¹⁵/₈)/6 |(-½)³|

|R₂| = ⁵/₁₂₈

8 0
3 years ago
Dose anyone know this problem if u so plz help!
Dennis_Churaev [7]
A=\dfrac{1}{2}(a+b)h+\dfrac{1}{2}\pi r%2\\&#10;a=8\\&#10;b=4\\&#10;h=4\\&#10;r=2\\&#10;A=\dfrac{1}{2}(8+4)\cdot4+\dfrac{1}{2}\pi \cdot 2^2\\&#10;A=24+2\pi=2(12+\pi)
7 0
4 years ago
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