Answer:
The probability that the mean of this sample is less than 16.1 ounces of beverage is 0.0537.
Step-by-step explanation:
We are given that the average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces.
A random sample of sixty-five 16-ounce beverage cans are selected
Let
= <u><em>sample mean amount of a beverage</em></u>
The z-score probability distribution for the sample mean is given by;
Z =
~ N(0,1)
where,
= population mean amount of a beverage = 16.18 ounces
= standard deviation = 0.4 ounces
n = sample of 16-ounce beverage cans = 65
Now, the probability that the mean of this sample is less than 16.1 ounces of beverage is given by = P(
< 16.1 ounces)
P(
< 16.1 ounces) = P(
<
) = P(Z < -1.61) = 1 - P(Z
1.61)
= 1 - 0.9463 = <u>0.0537</u>
The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9591.
Answer:
Option a) Mean
Mean is affected a lot by the change in the last observation as the median remains the same.
Step-by-step explanation:
we are given the following in the question:
Data set A: 64, 65, 66, 68, 70, 71, 72
Data set B: 64, 65, 66, 68, 70, 71, 720
For data set A, the mean and median are 68.
For data set B:
Formula:

Sorted data:
64, 65, 66, 68, 70, 71, 720

Clearly, 720 is the is a outlier.
As seen mean is affected a lot by the change in the last observation as the median remains the same.
Answer: 7
Step-by-step explanation: Imagine having 5 chocolate bars and then adding 2, or you could try counting with your fingers. Another method is writing a number line and going plus 2 from five so you can visualize it more.
Answer:
a ) dAt/dt = 50,24 in/min
dh/dt = - 0,125 in/min
Step-by-step explanation:
The area of the top is At :
At = π*r²
a) Tacking derivatives with respect to time:
dAt/dt = 2* π*r * dr/dt
At t = t₁ r = 16 in and dr/dt = 0,5
Then
dAt/dt = 2*3,14*16*0,5 in/min
a ) dAt/dt = 50,24 in/min
b) The volume of the cylinder is:
Vc = π*r²*h ( where h is the heigh of the cylinder )
Tacking derivatives with respect to time
dVc/dt = 2* π*r*h*dr/dt + π*r²*dh/dt
But dVc/dt = 0 since the volume remains constant, then:
π*r²*dh/dt = - 2* π*r*h*dr/dt
r*dh/dt = - 2*h*dr/dt
dh/dt = - 2*0,5*2/16 in/min
dh/dt = - 0,125 in/min
i believe it would be 5.25
12-5=7
7*12=84
84/ 16 = 5.25
i hope this helps