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juin [17]
3 years ago
12

Write an equation in point slope form using the following information

Mathematics
1 answer:
koban [17]3 years ago
8 0
Because it parallel to y=2x-5 the slope m = 2.
Use the general form
Y-y1=m(x-x1)

Y-(-3)) =2(x-5)
Y+3 =2x-10)
Y = 2x -13
-
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The average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 oun
Artist 52 [7]

Answer:

The probability that the mean of this sample is less than 16.1 ounces of beverage is 0.0537.

Step-by-step explanation:

We are given that the average amount of a beverage in randomly selected 16-ounce beverage can is 16.18 ounces with a standard deviation of 0.4 ounces.

A random sample of sixty-five 16-ounce beverage cans are selected

Let \bar X = <u><em>sample mean amount of a beverage</em></u>

The z-score probability distribution for the sample mean is given by;

                          Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean amount of a beverage = 16.18 ounces

           \sigma = standard deviation = 0.4 ounces

           n = sample of 16-ounce beverage cans = 65

Now, the probability that the mean of this sample is less than 16.1 ounces of beverage is given by = P(\bar X < 16.1 ounces)

   P(\bar X < 16.1 ounces) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{16.1-16.18}{\frac{0.4}{\sqrt{65} } } ) = P(Z < -1.61) = 1 - P(Z \leq 1.61)

                                                    = 1 - 0.9463 = <u>0.0537</u>

The above probability is calculated by looking at the value of x = 1.61 in the z table which has an area of 0.9591.

8 0
3 years ago
Here are two datasets:
fiasKO [112]

Answer:

Option a) Mean

Mean is affected a lot by the change in the last observation as the median remains the same.

Step-by-step explanation:

we are given the following in the question:

Data set A: 64, 65, 66, 68, 70, 71, 72

Data set B: 64, 65, 66, 68, 70, 71, 720

For data set A, the mean and median are 68.

For data set B:

Formula:

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1124}{7} = 160.57

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data:

64, 65, 66, 68, 70, 71, 720

\text{Median} = \dfrac{7+1}{2}^{th} \text{ term} = 4^th\text{ term} = 68

Clearly, 720 is the is a outlier.

As seen mean is affected a lot by the change in the last observation as the median remains the same.

5 0
3 years ago
2+5 is going to be a long one ne
andrew-mc [135]

Answer: 7

Step-by-step explanation: Imagine having 5 chocolate bars and then adding 2, or you could try counting with your fingers. Another method is writing a number line and going plus 2 from five so you can visualize it more.

3 0
3 years ago
Read 2 more answers
A pizza chef begins to spin a constant volume of dough to make a pie by spinning and tossing the dough into the air, such that t
Alexxandr [17]

Answer:

a ) dAt/dt  =  50,24 in/min

dh/dt  =  -  0,125 in/min

Step-by-step explanation:

The area of the top is At :

At = π*r²

a)  Tacking derivatives with respect to time:

dAt/dt  =  2* π*r * dr/dt

At   t  =  t₁      r  = 16 in     and  dr/dt =  0,5

Then

dAt/dt  =  2*3,14*16*0,5   in/min

a ) dAt/dt  =  50,24 in/min

b) The volume of the cylinder is:

Vc =  π*r²*h     ( where h is the heigh of the cylinder )

Tacking derivatives with respect to time

dVc/dt  =  2* π*r*h*dr/dt  +  π*r²*dh/dt

But  dVc/dt  = 0  since the volume remains constant, then:

π*r²*dh/dt  = -  2* π*r*h*dr/dt

r*dh/dt  =  -  2*h*dr/dt

dh/dt  = - 2*0,5*2/16  in/min

dh/dt  =  -  0,125 in/min

4 0
3 years ago
[(12-5). 12] ÷16=?<br>can I please get some help on this? It would be greatly appreciated
lina2011 [118]

i believe it would be 5.25

12-5=7

7*12=84

84/ 16 = 5.25

i hope this helps

8 0
3 years ago
Read 2 more answers
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