Answer:
N, B, Be, C
Explanation:
N (Nitrogen) has 14.0067 B (Boron) has 10.81 Be (Beryllium) has 9 and C (Carbon) has 12
Answer:
Another name for light is ¨Electromagnetic Radiation, luminous energy, and/or radiant energy.¨
Explanation:
Light is the electromagnetic radiation that´s capable of causing a visual sensation and has wavelengths from about 380 to about 780 nanometres. Electromagnetic radiation includes Radio Waves, Microwaves <u>(used in microwaves)</u>, Infrared Radiation <u>(heat)</u>, Visible Light <u>(the colors we see)</u>, Ultraviolet <u>(the UV radiation that causes sunburns)</u>, X-Rays <u>(used in medical X-Rays)</u>, and Gamma Rays <u>(which can be used to treat cancer)</u>. Light waves are transverse waves because they only travel east or west, but their crests and troughs face north and south (if desplayed on a coordinate grid). They wouldn´t be longitudinal waves because these waves don´t have vertical crests and troughs.
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Answer:
May 17
Explanation:
When it refers to 0% light it describe a new moon, from a new moon to a full Moon are 14 days, then if you start a full moon on May 3 and you add 14 days it means that the next new Moon would be on May 17.
B. the crystals have abundant room to grow in their hollow surroundings
Explanation:
Minerals in geodes form spectacular euhedral crystals because the crystals have abundant room to grow in their hollow surroundings.
Euhedral crystals are crystals that have well formed and defined faces. The opposite term for euhedral is anhedral. Anhedral crystals lacks crystal faces.
When a crystal have abundant room to grow in their hollow surroundings, they grow and develop well without any alteration of their faces.
Crystal faces are destroyed when crystals don't have spaces to grow and they touch each other.
Learn more:
Platinum crystals brainly.com/question/5048216
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Answer:
Explanation:
Utilizing Rydber's equation:
ΔE = Z²Rh ( 1/n₁² - 1/n₂²) and substituting the values given ( using the Rydbers constant value in Joules ), we have
n=1 to n= infinity
ΔE = 3² x (1/1² - 0) x 2.18 x 10⁻^18 J = 2.0 x 10⁻¹⁷ J (1/infinity is zero)
n= 3 to n= infinity
ΔE = 3² x (1/3² - 0) x 2.18 x 10⁻^18 J = 2.28 x 10^-18 J
b. The wavelength of the emitted can be obtained again by using Rydberg's equation but this time use the constant value 1.097 x 10⁷ m⁻¹ given in the problem .
1/λ = Z²Rh (1/n₁² - 1/n₂²) 10 ⁻¹ = 3² x 1.097 x 10⁷ m⁻¹ x (1/1² - 1/3²) m⁻¹
1/λ =8.8 x 10⁷ m⁻¹ ⇒ λ =1.1 x 10^-8 m
λ = 1.1 x 10^-8 m x 1 x 10⁹ nm/m = 11 nm
