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Gala2k [10]
3 years ago
15

What is the length of TH, when T (10,7), and H (-4,3)?

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Answer:

TH=14.56

Step-by-step explanation:

Given: T(10,7) and H(-4,3)

Distance formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\text{Length of TH }=\sqrt{(-4-10)^2+(3-7)^2}

                           =\sqrt{14^2+4^2}

                           =\sqrt{196+16}

                           =\sqrt{212}

                           \approx 14.56

Hence, The length of TH \sqrt{212}\approx 14.56

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Which points are 4 units apart?
xz_007 [3.2K]

The points that are 4 units apart are B and D

<h3>Complete question</h3>

Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).

B and C

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<h3>How to determine the points?</h3>

To do this, we simply calculate the distance using the following equation

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2

Using the given points, we have:

BC = \sqrt{(3+ 1)^2 + (-6 -0)^2} = 7.2

CD = \sqrt{(-1 - 3)^2 + (0 +2)^2} = 4.5

AC = \sqrt{(-2 + 1)^2 + (4 -0)^2} = 4.1

BD = \sqrt{(3 - 3)^2 + (-6 +2)^2} = 4

Hence, the points that are 4 units apart are B and D

Read more about distance at:brainly.com/question/15821277

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Step-by-step explanation:

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