Question

Write an equation of the line that passes through the points (-1,8) and (2,-4)

Answer 1

Answer:

The equation of the line that passes through the points (-1,8) and (2,-4) is:

• $y=-4x+4$

Step-by-step explanation:

Given the points

• (-1,8)

• (2,-4)

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-1,\:8\right),\:\left(x_2,\:y_2\right)=\left(2,\:-4\right)$

$m=\frac{-4-8}{2-\left(-1\right)}$

$m=-4$

As the point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

where m is the slope.

substituting the values m = -4 and the point (-1,8)

$y-\(8\right=-4\left(x-\left(-1\right)\right)$

$y-8 = -4(x+1)$

Add 8 to both sides

$y-8+8=-4\left(x+1\right)+8$

$y=-4x+4$

Therefore, the equation of the line that passes through the points (-1,8) and (2,-4) is:

• $y=-4x+4$

Answer 2

Answer:

y=mx+b

y=-4x +12 is your equation

m= yo

your slope

Step-by-step explanation: