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OlgaM077 [116]
4 years ago
6

A candy distributor needs to mix a 40% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 41% f

at-content chocolate. How many kilograms of each kind of chocolate must they use? A) Write an equation that uses the information as it is given above that can be used to solve this problem. Use x as your variable to represent the quantity of 40% fat-content chocolate. Equation: B) Answer: They must mix ?Kilograms of the 40% chocolate and ?Kilograms of the 50% chocolate.
Mathematics
1 answer:
UNO [17]4 years ago
4 0

Answer:

The kilograms of chocolate for the 40% fat content (1st chocolate) = 90kg

The kilograms of chocolate for the 50% fat content (2nd chocolate) = 10kg

Step-by-step explanation:

A candy distributor needs to mix a 40% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 41% fat-content chocolate. How many kilograms of each kind of chocolate must they use?

Let us represent

Kilograms of first chocolate = x

Kilograms of second chocolate = y

A candy distributor needs to mix a 40% fat-content chocolate with a 50% fat-content chocolate to create 100 kilograms of a 41% fat-content chocolate.

Hence:

40% × x + 50% × y = 41% × 100

0.40x + 0.50y = 0.41× 100

0.40x + 0.50y = 41.......Equation 1

x + y = 100kg ......Equation 2

x = 100 - y

Substitute 100 - y for x

0.40(100 - y) + 0.50y = 41

40 - 0.40y + 0.50y = 41

Collect like terms

- 0.40y + 0.50y = 41 - 40

0.10y = 1

y = 1/0.1

y = 10.

Therefore, the kilograms of chocolate for the 50% fat content (2nd chocolate) = 10kg

Remember:

x = 100 - y

x = 100kg - 10kg

x = 90kg

The kilograms of chocolate for the 40% fat content (1st chocolate) = 90kg

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alexira [117]
So you make them the same common denominator
As you see, 2/10 = 8/40
2/4 = x/40, multiply by 10
2/4 = 20/40
Then add because same denominator
Now you would get:
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