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UNO [17]
3 years ago
11

What is the distance between the two numbers on a number line? -7/4 and 3/8

Mathematics
2 answers:
ankoles [38]3 years ago
8 0

Answer: -2 1/8

Step-by-step explanation: Just subtract -7/4 and 3/8, and you’Lol get the answer. They putted a positive 2 1/8 to confused you with the real answer, and most people do get tricked. I honestly didn’t tell you how to do it, but just get the question over with dude.

Levart [38]3 years ago
3 0
To find the distance between any two real numbers, take the greater number (the one lying farthest to the right on a number line) and subtract the lesser number ( the on lying farthest to the left)
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Help plzzz I really need help
Alex17521 [72]
You would divide. 
Think of it as a 'real' situation. You are holding a piece of wire and you cut it into 3 pieces so you have 'divided' it into 3 pieces. 
62.4 divided by 3 = ??
The answer is 20.8 per piece 

To check your answer you can take 20.8 and multiply it by 3.


7 0
4 years ago
Write the equation of a line that passes through the point (12, 5) and has a slope of -3<br>​
Pavlova-9 [17]

Answer:

y - 5 = -3(x - 12)

General Formulas and Concepts:

<u>Algebra I</u>

Coordinates (x, y)

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Step-by-step explanation:

<u>Step 1: Define</u>

Point (12, 5)

Slope <em>m</em> = -3

<u>Step 2: Write Function</u>

<em>Plug in variables into the general formula.</em>

  1. Substitute [PSF]:                    y - 5 = -3(x - 12)
3 0
3 years ago
3^(x-2) = 5^(x+1)
Molodets [167]

Answer:

x=log_{\frac{3}{5} }(45)

x-2=log_{3}(5)x+log_{3}(5)  \\x-log_{3}(5)x=log_{3}(5)+2\\(1-log_{3}(5))x=log_{3}(5)+2\\x=\frac{log_{3}(5)+2}{1-log_{3}(5)} \\x=\frac{log_{3}(5)+log_{3}(3^2)}{log_{3}(3)-log_{3}(5)} \\x=\frac{log_{3}(5x3^2)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(5x9)}{log_{3}(\frac{3}{5} )} \\x=\frac{log_{3}(45)}{log_{3}(\frac{3}{5} )}\\x=log_{\frac{3}{5}}(45)

Hope this helps you :)

8 0
3 years ago
Which of the following is not the graph of a function of x?​
Paraphin [41]

Answer:

i think it's the third one

6 0
3 years ago
Which transformations are needed to change the parent cosine function to y = 0.35 cosine (8 (x minus startfraction pi over 4 end
Nataliya [291]

The transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

  • vertical stretch of 0.35
  • horizontal compression of period of \dfrac{\pi}{4}
  • phase shift of  \dfrac{\pi}{4} to right

<h3>How does transformation of a function happens?</h3>

The transformation of a function may involve any change.

Usually, these can be shift horizontally (by transforming inputs) or vertically (by transforming output), stretching (multiplying outputs or inputs) etc.

If the original function is y=f(x)A, assuming horizontal axis is input axis and vertical is for outputs, then:

  • Horizontal shift (also called phase shift):y=f(x+c)
  1. Left shift by c units: earlier)
  2. Right shift by c units: y=f(x-c) output, but c units late)
  • Vertical shift:
  1. Up by d units: y=f(x)+d
  2. Down by d units: y=f(x)-d
  • Stretching:
  1. Vertical stretch by a factor k: y=k\times f(x)
  2. Horizontal stretch by a factor k: y=f(\dfrac{x}{k})}

For this case, we're specified that:

y = cos(x) (the parent cosine function) was transformed to

y=0.35cos(8(x-\pi/4)

We can see its vertical stretch by 0.35, right shift by horizontal stretch by 1/8

Period of cos(x) is of  length. But 1.8 stretching makes its period shrink to

\dfrac{2\pi}{8}=\dfrac{\pi}{4}

Thus, the transformations that are needed to change the parent cosine function to y = 0.35×cos(8(x-π/4)) are:

vertical stretch of 0.35

horizontal compression to period of  (which means period of cosine is shrunk to  which originally was  )

phase shift of  to right

Learn more about transformation of functions here:

brainly.com/question/17006186

7 0
3 years ago
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