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fenix001 [56]
3 years ago
7

A man earned x pesos in 10 days and spent y pesos during each of those days. Write an expression to determine how many pesos he

saved per day
Mathematics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:  \dfrac{x}{10}-y

Step-by-step explanation:

Given : A man earned x pesos in 10 days and spent y pesos during each of those days.

i.e. Total earning in 10 days = x

Earning per day =\dfrac{x}{10}    [By unitary method]    (1)

Money spent per day =y      (2)

We know that

\text{Savings = Money earned - Money spent}

i.e. Subtract (2) from (1), we get

\text{Savings = }\dfrac{x}{10}-y

Hence, the expression to determine how many pesos he saved per day will be:-

\dfrac{x}{10}-y

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Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

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White = 6

Black = 9

Required

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The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

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Step-by-step explanation:

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The area of a rectangle = length * width

For rectangle 1, length = 12 m, width = 3 m

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