Y= -3 - 2x because all you have to do is move the 2x over to have an x and a y on different sides, and in order to do that you do the opposite so since it is a positive 2, you subtract it and make it negative
Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.
We can find m∠BCD like follows: m∠BCD=90°-45°=45<span>°
Now, m</span><span>∠DBC= 180°-(90°+45°)=45°
Remember that </span>

, so

We know that hypotenuse= BC= 3in and

=∠DBC)=45°, so replacing the values we get:

We can conclude that the segment CD is 2.12 in
Answer: Linear
Step-by-step explanation:
The equation y=mx+b which is used for this equation is a linear function.