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rosijanka [135]
3 years ago
12

Give me the answer for this

Mathematics
1 answer:
Gala2k [10]3 years ago
4 0

Answer:

>

Step-by-step explanation:

because 16 is greater than 12

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THE ORIGINAL CARS Movie MADe 450
Marina86 [1]

Answer:

34% decrease

Step-by-step explanation:

(V1-V2)/V1x100

450-297=153

153/450=0.34

0.34 x 100=34

34% decrease

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3 years ago
What is the 4th equivalent fraction to <br> 5/6
Lady bird [3.3K]

Answer:

20/24

Step-by-step explanation: Hope this helps

3 0
2 years ago
Help please :) I will show the next questions in the other one so please answer them.
Yuki888 [10]

Answer:

Can you please take a better picture

Step-by-step explanation:

6 0
3 years ago
Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
Readme [11.4K]
<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

i.e. t=\dfrac{41.0-35.0}{\dfrac{3.7}{\sqrt{20}}}=7.252112359\approx7.25

Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.

We conclude that there is some significance difference between the mean score for sober women and 35.0.

3 0
3 years ago
A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres
VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

x^{1} *(x-4)^{3} becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x

8 0
2 years ago
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