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denis-greek [22]
3 years ago
12

Wassup brainly peeps, one thing i need for you guys is to answer this question and you can land onto the brainliest plane.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

(B) i think

Step-by-step explanation:

comment how it help

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I need help on this math problem.!!
vodomira [7]

x = 95°

the polygon has 5 sides so you do n - 2 which is (number of sides - 2) this gives us 3. now multiply 3 times 180, this gives us 540. now add up all the sides that you know, 104, 117, 100, 124, this is 445 now subract 445 from 540 and that is what gives us 95°

6 0
3 years ago
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Harriet has 3/4 tank of gas left in her car. if she needs 1/4 tank to go to her friends house and another 1/4 tank to get back h
pashok25 [27]
Ok so if you add the two 1/4's you will find how much gas she needs total to complete the trip. So do 1/4 + 1/4 and get 1/2. Next you can see that 3/4 is larger than 1/2, so she has enough gas.
Hope that helps!
3 0
3 years ago
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Y=1/2x +5<br> Y=-3/2x-7<br> Find x and y
gayaneshka [121]
I'm going to use the substitution method. 

If y = - 3/2 - 7, then:

1/2x + 5 = - 3/2x - 7

Combine like terms: 

4/2x = - 12. Mutiply both sides by 2/4 to get x = -12 (2/4)

Simplify to get:

x = - 6.

Plug - 6 back in for x in either equation.

Y = 1/2( - 6) + 5 which becomes Y = - 3 + 5.

X = - 6, Y = 2





8 0
3 years ago
What is the pattern to 1,2,4,7,11
Svetllana [295]

Answer:

1+1=2

2+2=4

4+3=7

7+4=11

so the patter is number + natural numbers (serially)

Step-by-step explanation:

4 0
2 years ago
Simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BX-10%7D" id="TexFormula1" title="\frac{1}{X-10}" alt="\frac{1}{X-10}
mr Goodwill [35]

In the second fraction, factorize the denominator:

x^2-9x-10=(x-10)(x+1)

Then we have, as long as x\neq10,

\dfrac1{x-10}\div\dfrac{9x}{x^2-9x-10}=\dfrac{\frac1{x-10}}{\frac{9x}{(x-10)(x+1)}}=\dfrac1{\frac{9x}{x+1}}=\dfrac{x+1}{9x}

which you could also write as

\dfrac{x+1}{9x}=\dfrac x{9x}+\dfrac1{9x}=\dfrac19+\dfrac1{9x}

4 0
2 years ago
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