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marissa [1.9K]
3 years ago
12

For both waves on strings and sound waves in tubes, For both waves on strings and sound waves in tubes,

Physics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

option (B) is correct.

Explanation:

frequency is directly proportional to the speed of wave and inversely proportional to the wavelength.

For string

frequency , f = v/λ

for tube

frequency ∝ 1 / λ

So, we can say that the frequency is inversely proportional to the wavelength.

thus, the higher the mode means shorter the wavelength.

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Which of the following is not a true statement?<br> v=at<br> O art
shepuryov [24]

Answer:

t = Δa / v

Explanation:

To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:

Acceleration = change in velocity / time

a = Δv / t ..... (1)

But

Δv = v₂ – v₁

Substitute the value of Δv into equation (1)

a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

a = Δv / t

Cross multiply

Δv = at .... (3)

From equation (1), make t the subject of the equation.

a = Δv / t

Cross multiply

at = Δv

Divide both side by a

t = Δv /a ...... (4)

From circular motion, centripetal's force is given by:

F = mv²/r

F = ma꜀

Therefore,

ma꜀ = mv²/r

Cancel out m

a꜀ = v²/r

SUMMARY:

a = Δv / t

a = v₂ – v₁ / t

Δv = at

t = Δv /a

a꜀ = v²/r

Considering the options given in question above, t = Δa / v is not a true statement.

8 0
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Answer:

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Explanation:

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Answer:

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