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marissa [1.9K]
3 years ago
12

For both waves on strings and sound waves in tubes, For both waves on strings and sound waves in tubes,

Physics
1 answer:
Vsevolod [243]3 years ago
3 0

Answer:

option (B) is correct.

Explanation:

frequency is directly proportional to the speed of wave and inversely proportional to the wavelength.

For string

frequency , f = v/λ

for tube

frequency ∝ 1 / λ

So, we can say that the frequency is inversely proportional to the wavelength.

thus, the higher the mode means shorter the wavelength.

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