Which statement is true regarding the vectors shown.

While getting buff at the gym you lift a bunch of weights applying 1000N of force to lift them from the ground to a height of 2m

slega [8]

A. 2000 J............

8 0

3 years ago

How does the kinetic energy of a charge change as the charge moves under the effect of an electric field from higher potential t

77julia77 [94]

Answer:The kinetic energy will decrease.

Explanation:As potential energy increases kinetic energy will increase, as kinetic or potential energy decreases, the kinetic or potential energy will decrease

7 0

3 years ago

One day, Pinki was ironing the clothes in her room. After half an hour of ironing, the light went off and Pinki went outside to

Triss [41]

Answer:

(a) An electric iron works on the heating effect of electric current

(b) The heating effect of an electric current is the tendency for electric current to cause the temperature of the material through which it is flowing to rise due to the resistance of the material

The heating effect, 'E', is given by the formula, E = I²·R·t

Where;

I = The current flowing

R = The resistance of the material

t = The time the material takes to heat up

(c) The values showed by Pinki here is the value of care, concern and prevention, to prevent the harmful effect of the high heat on the skin of her daughter

Explanation:

3 0

3 years ago

A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

8 0

3 years ago

Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po

Montano1993 [528]

Answer:

A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

Explanation:

A) Light passing through a polarizer must comply with the / bad law

I = Io cos2 tea

Where is at the angle of the polarizer and incident light

I = Io cos2 45

I = Io 0.578

Therefore the beam intensity is 0.578 of the incident intensity

.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

3 0

4 years ago