(a) The work done by the applied force is 26.65 J.
(b) The work done by the normal force exerted by the table is 0.
(c) The work done by the force of gravity is 0.
(d) The work done by the net force on the block is 26.65 J.
<h3>
Work done by the applied force</h3>
W = Fdcosθ
W = 14 x 2.1 x cos25
W = 26.65 J
<h3>
Work done by the normal force</h3>
W = Fₙd
W = mg cosθ x d
W = (2.5 x 9.8) x cos(90) x 2.1
W = 0 J
<h3>Work done force of gravity</h3>
The work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.
<h3> Work done by the net force on the block</h3>
∑W = 0 + 26.65 J = 26.65 J
Thus, the work done by the applied force is 26.65 J.
The work done by the normal force exerted by the table is 0.
The work done by the force of gravity is 0.
The work done by the net force on the block is 26.65 J.
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Answer:
<h2>33.53m/s</h2>
Explanation:
Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.
Using the conversion 1 mile = 1609.34m and 1 hour = 3600 seconds
75 miles perhour = 75miles/1 hour
75miles/1 hour (in m/s) = 75miles*1609.34m* 1 hour/1mile * 1 hour * 3600s *
= 75 *1609.34m* 1 /1 * 1 * 3600s
= 120,700.5m/3600s
= 33.53m/s
<em>Hence the maximum speed limit on interstate 10 in metre per seconds is 33.53m/s</em>
A) 0
because all of the forces cancel out, so it is not moving with balanced forces.
True.
I think that’s the answer.
<span>Active Galactic Nuclei.</span>
