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3 years ago

If you push on the wall with a force of 400 N, what is the magnitude of the force at the wall exerts on you?

Physics

1 answer:

Inessa05 [86]3 years ago

7 0

Answer:

400 N

Explanation:

Due to action-Reaction, the wall pushes back on the person with a force of equal magnitude and in opposite direction to the force exerted by the person.

So the magnitude must be also 400 N.

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Physical values in the real world have two components: magnitude and

Nadusha1986 [10]

Answer:

Dimension.

Explanation:

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3 years ago

If a certain mass of mercury has a volume of 0.002m3 at a temperature of 20°C, what will be the volume at 50°C,

USPshnik [31]

Set this up as a proportion.

.002 m^3/20 degrees = x/50 degrees

solve for x

x = .005 m^3

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3 years ago

Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s

Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{40}{5} \\$

We have the final answer as

Hope this helps you

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3 years ago

What is the radius of a communications satellite’s orbital path that is in a uniform circular orbit around Earth and has a perio

pantera1 [17]

If the period of a satellite is T=24 h = 86400 s that means it is in geostationary orbit around Earth. That means that the force of gravity Fg and the centripetal force Fcp are equal:

Fg=Fcp

m*g=m*(v²/R),

where m is mass, v is the velocity of the satelite and R is the height of the satellite and g=G*(M/r²), where G=6.67*10^-11 m³ kg⁻¹ s⁻², M is the mass of the Earth and r is the distance from the satellite.

Masses cancel out and we have:

G*(M/r²)=v²/R, R=r so:

G*(M/r)=v²

r=G*(M/v²), since v=ωr it means v²=ω²r² and we plug it in,

r=G*(M/ω²r²),

r³=G*(M/ω²), ω=2π/T, it means ω²=4π²/T² and we plug that in:

r³=G*(M/(4π²/T²)), and finally we take the third root to get r:

r=∛{(G*M*T²)/(4π²)}=4.226*10^7 m= 42 260 km which is the height of a geostationary satellite.

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3 years ago

a dart player throws a dart at speed of 12.9m/s. the dart hits the board 0.35m below the height from which it was theown. how fa

Veseljchak [2.6K]

1. Find the amount of time the dart is in the air using the equation dy...
2. Vy initial is 0, and the only force acting on the dart while it is in the air is gravity so the acceleration of the dart in the y direction is 9.8.
3. Plug in the time you found and Vx = 12.9 to get Dx

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3 years ago