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marysya [2.9K]
4 years ago
7

What happens to particles in a substance changes state

Physics
2 answers:
Y_Kistochka [10]4 years ago
8 0
Rephrase you have to be specific......<span>MELTING. When a solid is heated, the </span>particles<span> are given more energy and start to vibrate faster. ... At this point the solid melts into liquid. The temperature at which this </span>change<span> from solid to liquid </span>happens<span> is called the melting point.</span>
Kobotan [32]4 years ago
5 0
Melting 
get a A+++ ;)
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Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
DochEvi [55]

Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

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3 years ago
Liquid water heats up and cools down slowly. What causes this property?
Alja [10]

Answer:

water forms hydrogen bonds

Explanation:

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An object at rest stays at rest and an object in stays in motion with the same speed and in the same direction unless acted upon
IrinaVladis [17]

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3 years ago
A measurement has high<br> when it is very close to the<br> true value?
jarptica [38.1K]

Answer:

Accuracy

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Accuracy means making measurements that are close to the value precision means making measurement that are close in value to eachother but not necessarily close to the true value.

I hope this helps! If not sorry.

7 0
3 years ago
A car accelerates uniformly from rest to 16.4 m/s in 4.35 s along a level stretch of road. Ignoring friction, determine the aver
Pachacha [2.7K]

Answer:

(a) Average power required to accelerate is 2.87 x 10⁴ W

(b) Average power is required to accelerate is 6.25 x 10⁴ W

Explanation:

Given :

Initial speed of car, u = 0 m/s

Final speed of the car, v = 16.4 m/s

Time, t = 4.35

Initial kinetic energy of car, K₁ = 0

Final kinetic energy of car, K₂ = (mv²)/2

Here m is the mass of the car.

Applying Work-Energy theorem,

Work done = Change in kinetic energy

W = ΔK    ....(1)

Power is defined as work done per unit time. So,

P = W/t

From equation (1), the above equation becomes:

P = ΔK/t

P = (K₂ - K₁)/t

P = (mv²)/(2t)   .....(2)

(a) Weight of the car, W = 9.11 x 10³ N

But, W = m x g

Here g is acceleration due to gravity.

So, m = W/g

Thus, the equation (2) becomes:

P=\frac{Wv^{2} }{2gt}      ....(3)

Substitute the suitable values in the above equation.

P=\frac{9.11\times10^{3}\times (16.4)^{2} }{2\times9.8\times4.35}

P = 2.87 x 10⁴ W

(b) Weight of the car, W = 1.98 x 10⁴ N

Substitute this value of W in equation (3) with other suitable values.

P=\frac{1.98\times10^{4}\times (16.4)^{2} }{2\times9.8\times4.35}

P = 6.25 x 10⁴ W

8 0
3 years ago
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