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2 years ago

Evaluate the expression when y=-6.y^2+5y-2

Mathematics

2 answers:

dedylja [7]2 years ago

5 0

Answer:

Step-by-step explanation:

Sometimes when evaluating polynomials, it is easier if you write them in Horner form:

(y +5)y -2

For y = -6, this is ...

(-6 +5)(-6) -2 = (-1)(-6) -2 = 6 -2 = 4

The value of your expression is 4.

Ratling [72]2 years ago

3 0

Answer:

this glizzy

Step-by-step explanation:

blow this glizzy u madd u wrong answer

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g Which of the following is equivalent to P( A|B)? a. P(A and B) b. P(B|A) c. P(A)/P(B) d. None of these choices.

Scilla [17]

Answer:

The correct option is D.

But option B is correct if P(A) = P(B).

Step-by-step explanation:

P(A|B) is read as "The probability of A given B".

It is different from the options A, B, and C.

It is equal to option B only if the probability of A is equal to the probability of B. That is P(A|B) = P(B|A) if P(A) = P(B).

6 0

2 years ago

Factor completely<br> (X^2 + x - 6) (2x^2 + 4x) =

Vikki [24]

Answer:

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

Step-by-step explanation:

(X^2 + x - 6) (2x^2 + 4x) =

Let's open the brackets carefully

x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x

= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

8 0

3 years ago

Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be ac

Likurg_2 [28]

For this problem, the most accurate is to use combinations

Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are $nC_r = \frac{ n! }{r! (n-r)!}$

n represents the amount of things you can choose and choose r from them

You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

$P = \frac{_{117}C_3}{_{120}C_3}$

Where $_{117}C_3$ is the number of ways to select 3 non-defective components from 117 non-defective components and $_{120}C_3$ is the number of ways to select 3 components from 120.

$_{117}C_3 = 260130$

$_{120}C_3 = 280840$

So:

$P = \frac{260130}{280840} = 0.927$

Finally, the probability that at least one of the selected components is defective is:

$P = 1-0.927 = 0.0737$

P = 7.4%

3 0

3 years ago

Claire is painting some doors that are all the same size. She used 2 liters of paint to cobe 1 3/5 doors. How many liters of pai

Deffense [45]

Answer:

$1 \dfrac{1}{4} \ liters$

Step-by-step explanation:

Given that:

Claire uses 2 liters of paint to cover 1 3/5 doors

Then in order for her to paint 1 door, She will need:

2 L = 1 3/5 door

x L = 1 door

$x (L) = \dfrac{2 L \times 1 door }{ 1 \dfrac{3}{5} \ door}$

$x (L) = \dfrac{2 L }{ 1 \dfrac{3}{5} }$

$x (L) = \dfrac{2 L }{ \dfrac{8}{5} }$

$x (L) = \dfrac{2 L\times 5 }{ 8 }$

$x (L) = \dfrac{10 \ L }{ 8 }$

$x(L) =1 \dfrac{1}{4} \ L$

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2 years ago

G(x) = 2x^2 and h(x) = .What is (g h)-1 and is it a function?

Andrews [41]

H(x) equals what? I think you've missed that detail. :)

3 0

3 years ago

Read 2 more answers

Evaluate the expression when y=-6.y^2+5y-2​

Evaluate the expression when y=-6.y^2+5y-2