Answer:
Evaluate 8P6 P 6 8 using the formula nPr=n!(n−r)! P r n = n ! ( n - r ) ! . 8!(8−6)! 8 ! ( 8 - 6 ) ! Subtract 6 6 from 8 8 . 8!(2)! 8 ! ( 2 ) ! Simplify 8!(2)! 8 !
Step-by-step explanation:
evaluate" usually means to put a value in for the variable, but you don't give us a value for p. also, it is unclear if you ...
It is c because 8x2=16 and 8x4=32 and so on
The right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
Let be an <em>exponential</em> function of the form 
, where 
and 
are <em>real</em> numbers. A <em>horizontal</em> asymptote exists when 
, which occurs for 
.
For this function, the <em>horizontal</em> asymptote is represented by 
and to change the value of the asymptote we must add the <em>parent</em> function by another <em>real</em> number (
), that is to say:
(1)
In this case, we must use 
to obtain an horizontal asymptote of -3. Thus, the right choice is: A <em>whole</em> number constant could have been <em>subtracted</em> from the <em>exponential</em> expression.
To learn more on asymptotes, we kindly invite to check this verified question: brainly.com/question/8493280
1.3062 in Expanded from is
1.3062=(1x1)+(3/10)+(0/100)+(6/100)+(2/10000)
<span> Hope this help:)</span>
